Educerie
Level

4 higher-level sections hidden.

Educerie · IB Diploma · Biology

Theme D Continuity and change · D2.3 Water potential

Level
SL and HL. Sections 9 to 12 are HL only. If you are SL, skip them; nothing in your papers tests them.
Themes (key concepts)
continuity and change, at the level of cells. Water is always moving in and out of cells; a cell stays the same size and shape only because the flows balance, or because it spends energy or builds a wall to make them balance. Change the solution around it and the cell changes, sometimes fatally.
The question this unit answers
what factors affect the movement of water into or out of cells, and how do plant and animal cells differ in how they deal with it?
Where it is examined
Paper 1A multiple choice; Paper 1B, where the plant-tissue experiment is the classic data question (percentage change, isotonic point, standard deviation and error bars, 4 to 6 marks); Paper 2 Section A short answers ("explain why a red blood cell bursts…", 2 to 3 marks). HL adds water potential calculations and "explain in terms of solute and pressure potential" questions of 3 to 5 marks.

What you must be able to do

You must be able toLevelWhat it looks like in the exam
Explain solvation: hydrogen bonds with polar solutes, attraction to positive and negative ionsSL, HL"Explain how sodium chloride dissolves in water" (3 marks)
State the direction of water movement in terms of solute concentration, using hypotonic, hypertonic and isotonicSL, HLPaper 1A item
Predict net water movement into or out of cells, and explain dynamic equilibriumSL, HL"Predict and explain…" (2 marks)
Measure length and mass changes of plant tissue, find the isotonic concentration, and use standard deviation, standard error and error barsSL, HLPaper 1B data question (4 to 6 marks)
Describe what happens to cells without a wall: bursting, crenation, contractile vacuoles, isotonic tissue fluidSL, HL"Explain why freshwater protists need contractile vacuoles" (3 marks)
Describe turgor and plasmolysis in cells with a wallSL, HL"Distinguish between a turgid and a plasmolysed cell" (2 marks)
Explain the medical use of isotonic solutions: intravenous fluids and organs for transplantSL, HL"Explain why donor organs are kept in isotonic solution" (2 marks)
Define water potential and state its reference point and unitsHL only"Define water potential" (2 marks)
Explain water movement from higher to lower water potentialHL onlyPaper 1A, or a 2-mark "explain"
Use ψw = ψs + ψp, including negative pressure potential in xylemHL onlyCalculation, 1 to 3 marks
Explain tissue changes in hypotonic and hypertonic solutions in terms of ψs and ψpHL only"Explain, in terms of water potential…" (4 marks)

Before you start

You need osmosis from B2.1: the net movement of water across a partially permeable membrane from lower to higher solute concentration, often through aquaporins. You need water's polarity and hydrogen bonding from A1.1. And you need the difference between a plant cell (wall, large vacuole) and an animal cell (neither).


1The idea in one paragraph

Water dissolves many substances because its molecules are polar and cluster round each solute particle. Where there are more solute particles, there are fewer water molecules free to move, so across a membrane that stops the solute, water moves on balance towards the side with more solute: from a hypotonic solution to a hypertonic one. A cell in a solution more dilute than itself gains water; in a more concentrated one it loses water; in an isotonic one the flows balance. Without a wall, a cell that gains too much water bursts, which is why animals keep their body fluids isotonic and freshwater protists pump water out. With a wall, a plant cell swells until the wall pushes back, and that pressure holds the plant up. At HL, all of this is put into one number, water potential, that tells you which way water will move.

2Water as a solvent: solvation

Solvation is the surrounding of a solute particle by solvent molecules. When the solvent is water, the solute dissolves if its particles attract water molecules more strongly than they attract each other. Figure 1 shows the three cases you need.

Figure 1 · Solvation: water molecules surround each solute particle Figure 1 · Solvation: water molecules surround each solute particle (a) A sodium ion (b) A chloride ion (c) A glucose OH group Na⁺ Cl⁻ δ− oxygens face the positive ion δ+ hydrogens face the negative ion C O hydrogen bonds polar molecules dissolve by hydrogen bonding with water Water's partial charges are attracted to ions and form hydrogen bonds with polar molecules.
Figure 1 · Solvation: water molecules surround each solute particle

A water molecule is polar: its oxygen carries a slight negative charge (δ−) and its two hydrogens slight positive charges (δ+).

  • Positive ions, such as Na⁺, attract the δ− oxygen ends of water molecules. The water molecules crowd round the ion with their oxygens facing in.
  • Negative ions, such as Cl⁻, attract the δ+ hydrogen ends. The water molecules face the other way round.
  • Polar molecules, such as glucose with its –OH groups, form hydrogen bonds with water molecules.

In each case the solute particle ends up inside a shell of water molecules, separated from the other solute particles. That is what "dissolved" means. The shell also matters for the rest of this page: water molecules held round solute particles are less free to move, which is the root of osmosis.

3Which way water moves: hypotonic, hypertonic and isotonic

The guide asks you to describe water movement in terms of solute concentration, not water concentration, and with three comparison words.

  • Hypotonic: having a lower solute concentration than the solution it is being compared with.
  • Hypertonic: having a higher solute concentration.
  • Isotonic: having the same solute concentration.

All three are comparisons, so always say what with: "hypotonic to the cytoplasm".

Water moves by osmosis from a hypotonic solution to a hypertonic one: from lower solute concentration to higher.

Figure 2 shows why the word "net" matters.

Figure 2 · Osmosis: net movement of water towards the higher solute concentration Figure 2 · Osmosis: net movement of water towards the higher solute concentration (a) Different concentrations hypotonic lower solute concentration hypertonic higher solute concentration net flow of water (b) Isotonic equal flows dynamic equilibrium: water still moves, but no net change dashed line: partially permeable membrane; circles: solute particles Water crosses both ways all the time. Net movement is from hypotonic to hypertonic; isotonic means no net flow.
Figure 2 · Osmosis: net movement of water towards the higher solute concentration

Water molecules cross the membrane in both directions all the time. In panel (a), more cross from the hypotonic side, where more of them are free, than cross back from the hypertonic side, so there is a net movement towards the hypertonic side. In panel (b) the solutions are isotonic. Water still crosses, but equally in both directions, so the volume on each side stays the same. That is dynamic equilibrium: constant movement, no net change. "No water moves in an isotonic solution" is wrong.

4Water moving into and out of cells

The cytoplasm and vacuole of a cell are solutions, and the plasma membrane is partially permeable. So a cell behaves exactly like one side of Figure 2.

  • Surroundings hypotonic to the cell (for example, pure water): net movement of water into the cell.
  • Surroundings hypertonic to the cell (for example, strong salt solution): net movement of water out of the cell.
  • Surroundings isotonic: no net movement; the cell's volume stays constant.

5Measuring it: plant tissue in a range of solutions

The standard practical measures how pieces of plant tissue change when bathed in solutions of different concentrations, and uses the results to find the concentration that is isotonic with the tissue.

Method in outline. Cut cylinders of one tissue (carrot, potato, beetroot) with a cork borer, trim them to the same length, and blot and weigh or measure each. Place replicate pieces in a range of sucrose or salt solutions, for example 0.0 to 0.5 mol dm⁻³, at the same temperature. After a fixed time, often 30 minutes to a few hours, blot them dry the same way and measure again. Pieces never start identical, so calculate the percentage change for each piece:

percentage change = (final − initial) ÷ initial × 100

The data. The table gives invented results for carrot cylinders, all 50.0 mm long at the start, five repeats at each concentration.

Sucrose / mol dm⁻³0.00.10.20.30.40.5
Mean change in length / %+7.8+4.6+1.5−1.9−4.8−7.0
Standard deviation / %0.320.320.470.240.200.32
Standard error / %0.140.140.210.110.090.14

Standard deviation and standard error. The standard deviation (SD) measures how spread out the repeats are around their mean. The standard error (SE) estimates how precisely the mean itself is known; it is the SD divided by the square root of the number of repeats, so it shrinks as you take more repeats. You do not need to memorise the formulae (a calculator or spreadsheet function does it), but you should see once how the numbers arise. Here are the five repeats at 0.2 mol dm⁻³.

final lengths / mm: 50.60, 50.95, 50.50, 51.05, 50.65
% changes: +1.2, +1.9, +1.0, +2.1, +1.3 → mean = 7.5 ÷ 5 = +1.5
deviations from mean: −0.3, +0.4, −0.5, +0.6, −0.2
sum of squares = 0.09 + 0.16 + 0.25 + 0.36 + 0.04 = 0.90
SD = √(0.90 ÷ (5 − 1)) = √0.225 = 0.47divide by n − 1 for a sample
SE = SD ÷ √n = 0.47 ÷ √5 = 0.21

Reading the graph. Figure 3 plots the means, with error bars of ±1 SE.

Figure 3 · Carrot cylinders in sucrose solutions (invented data) Figure 3 · Carrot cylinders in sucrose solutions (invented data) Mean change in length / % Sucrose concentration / mol dm⁻³ 0.0 0.1 0.2 0.3 0.4 0.5 −10 −5 0 +5 +10 isotonic ≈ 0.24 tissue gained water tissue lost water Error bars show ±1 standard error of five repeats. The line crosses zero at about 0.24 mol dm⁻³.
Figure 3 · Carrot cylinders in sucrose solutions (invented data)

Below about 0.24 mol dm⁻³ the cylinders got longer: the solution was hypotonic to the cells, water entered by osmosis, and the cells swelled. Above it they got shorter: the solution was hypertonic, water left. Where the line crosses zero there was no net change, so that solution is isotonic with the tissue. Read it off the graph, or interpolate between the readings either side of zero:

isotonic ≈ 0.2 + 0.1 × 1.5 ÷ (1.5 + 1.94) = 0.2 + 0.044 = 0.24 mol dm-3

The error bars are short and no two of them overlap, so the differences between concentrations are larger than the scatter between repeats: the trend is reliable. If the bars of two neighbouring points overlapped widely, you could not be confident that those two means really differ.

Length or mass? The same experiment can record mass. SE lets you compare how reliable the two measurements are. In pure water, the same five carrot pieces (invented data) gave a mean length change of +7.8% with SE 0.14, and a mean mass change of +16.0% with SE 0.70.

length: SE ÷ mean = 0.14 ÷ 7.8 = 1.8%
mass: SE ÷ mean = 0.70 ÷ 16.0 = 4.4%

Relative to the size of the change, the mass readings scatter more, most likely because blotting leaves a variable film of liquid on each piece. In this data set length was the more reliable measure, though mass changes are larger and easier to detect.

6Cells without a cell wall

An animal cell, or a protist, has only a plasma membrane round it. It has nothing to resist swelling. Figure 4 (top row) shows a red blood cell in three solutions.

Figure 4 · Animal and plant cells in three solutions Figure 4 · Animal and plant cells in three solutions Hypotonic Isotonic Hypertonic red blood cell plant cell water enters: swells and bursts (haemolysis) normal shape: in and out flows balance water leaves: shrinks and crenates turgid: membrane pressed against the wall flaccid: no pressure on the wall plasmolysed: membrane pulls away from the wall thick black: cell wall · teal line: plasma membrane · pale blue: vacuole Without a wall, a cell bursts or shrivels. With one, it becomes turgid or plasmolysed but does not burst.
Figure 4 · Animal and plant cells in three solutions
  • Hypotonic: water enters, the cell swells and, because the membrane cannot stretch far, it bursts. For red blood cells this is called haemolysis.
  • Isotonic: no net movement; the cell keeps its normal biconcave shape.
  • Hypertonic: water leaves, the cell shrinks and its surface becomes wrinkled and spiky, called crenation.

Both extremes damage or kill cells, so organisms without walls must control their water balance.

Freshwater unicellular organisms. Pond water is strongly hypotonic to the cytoplasm of a protist such as Paramecium, so water enters by osmosis all the time. The cell would burst unless it removed the water. It does so with contractile vacuoles (Figure 5), which collect excess water from the cytoplasm and expel it through the membrane. This uses energy from ATP, and the vacuoles fill and empty continually.

Figure 5 · A freshwater protist pumps out water that enters by osmosis Figure 5 · A freshwater protist pumps out water that enters by osmosis cytoplasm: higher solute concentration than pond water water in water expelled (uses ATP) contractile vacuole nucleus Pond water is hypotonic to the cytoplasm, so water enters all the time and must be pumped out.
Figure 5 · A freshwater protist pumps out water that enters by osmosis

Multicellular organisms. Your cells are bathed in tissue fluid, which comes from blood plasma. If tissue fluid became hypotonic or hypertonic to the cells, they would swell or shrink, with harmful effects everywhere at once. So the solute concentration of blood, and therefore of tissue fluid, is kept isotonic with the cells, mainly by the kidneys (D3.3).

7Cells with a cell wall

Plant cells behave differently because of the wall, a strong layer of cellulose outside the membrane that is fully permeable to water and solutes. Figure 4 (bottom row) shows the three cases.

Hypotonic: turgor. Water enters, and the vacuole and cytoplasm swell until the plasma membrane presses against the wall. The wall is strong and barely stretches, so it pushes back. The pressure that builds up inside is turgor pressure. When it is high enough, water stops entering, even though the cell's contents are still more concentrated than the water outside. The cell is turgid, and it does not burst. Turgid cells pressing against each other are what keep a non-woody plant upright; a plant short of water loses turgor and wilts.

Isotonic: flaccid. No net movement of water; the membrane touches the wall but does not press on it. The cell is flaccid.

Hypertonic: plasmolysis. Water leaves, the vacuole and cytoplasm shrink, and the plasma membrane pulls away from the wall. This is plasmolysis. Because the wall is fully permeable, the space between wall and membrane fills with the external solution.

Without a wall, a cell in a hypotonic solution bursts. With a wall, it becomes turgid instead.

8Isotonic solutions in medicine

Anything that touches living tissue for long must be isotonic with it, for the reasons in section 6.

Intravenous fluids. Fluid given into a vein, for example to replace lost blood volume or to treat dehydration, mixes directly with blood plasma. It must be isotonic with the plasma, or red blood cells and other cells would swell and burst (if it were hypotonic) or shrink (if it were hypertonic). The commonest is normal saline, 0.9% sodium chloride, which is isotonic with blood plasma.

Organs for transplantation. A donor kidney or liver may be out of the body for hours before it is transplanted. It is bathed in a cold, isotonic solution. Isotonic, so its cells neither take up water and swell nor lose it and shrink; cold, to slow its metabolism and reduce the damage caused by lack of oxygen.

9HLWater potential

SL students can skip to section 13.

A turgid plant cell has sap more concentrated than pure water, yet water stops entering it: pressure is pushing back. Water potential combines solutes and pressure into one quantity.

Water potential (symbol ψ, psi, or ψw) is the potential energy of water per unit volume. It is impossible to measure the absolute potential energy of water, so values are given relative to pure water at atmospheric pressure and 20 °C, which is defined as zero. The units are kilopascals (kPa), because energy per unit volume has the same units as pressure.

10HLWater moves from higher to lower water potential

Water moves from a region of higher water potential to a region of lower water potential. The reason is energy. Like a ball rolling downhill, water moves spontaneously from where its potential energy is higher to where it is lower, and it keeps moving until the two water potentials are equal. Figure 6 shows this on a scale.

Figure 6 · Water moves from higher to lower water potential (HL) Figure 6 · Water moves from higher to lower water potential (HL) (a) The scale 0 −400 −800 −1200 ψ / kPa pure water cell X cell Y concentrated solution water moves down (b) Two neighbouring cells cell X ψs = −700 kPa ψp = +300 kPa ψw = −400 kPa cell Y ψs = −900 kPa ψp = +300 kPa ψw = −600 kPa net water movement X → Y −400 kPa is higher than −600 kPa Pure water at atmospheric pressure is 0 kPa; any solution is below zero. Water moves downhill.
Figure 6 · Water moves from higher to lower water potential (HL)

Because pure water is the zero, almost every value you meet is negative, and "higher" means less negative. −400 kPa is higher than −600 kPa. So in Figure 6(b) water moves from cell X to cell Y.

11HLSolute potential and pressure potential

For a cell with a wall, water potential has two components:

ψw = ψs + ψp

Solute potential (ψs) is the effect of dissolved solutes. Solutes hold water molecules round them (section 2) and lower its potential energy, so ψs is zero for pure water and negative for any solution; the more concentrated the solution, the more negative ψs. It can range from zero downwards, never above.

Pressure potential (ψp) is the effect of pressure. Pressure raises the potential energy of water. Inside a cell, the wall pushing back on the swollen protoplast creates a positive pressure, so ψp is generally positive inside cells. It is zero in a flaccid cell. It can also be negative: in xylem vessels, sap is pulled upwards under tension by transpiration (B3.2), and a pull is a negative pressure.

Work through the cells in Figure 6(b).

cell X: ψw = ψs + ψp = −700 + 300 = −400 kPa
cell Y: ψw = ψs + ψp = −900 + 300 = −600 kPa
−400 > −600, so water moves from X to Y

A second example: sap in a xylem vessel with a solute potential of −100 kPa, under a tension that gives a pressure potential of −600 kPa.

ψw = −100 + (−600) = −700 kPa

The xylem sap has a lower water potential than the root cells around it, which is why water is drawn from the roots into the xylem.

12HLPlant tissue in hypotonic and hypertonic solutions, explained

Now the practical in section 5 can be explained exactly. Take cell X again: ψs = −700 kPa, ψp = +300 kPa, ψw = −400 kPa. Figure 7 shows, for a typical cell, how the three potentials change as the protoplast gains or loses water.

Figure 7 · The components of water potential as a plant cell fills (HL) Figure 7 · The components of water potential as a plant cell fills (HL) Potential / kPa Relative volume of the protoplast −1200 −800 −400 0 +400 +800 0.90 1.00 1.05 1.10 1.15 ψp ψs ψw incipient plasmolysis (ψp = 0) fully turgid (ψw = 0) plasmolysed As water enters, ψp rises from zero and ψs rises slightly; ψw climbs to zero when the cell is fully turgid.
Figure 7 · The components of water potential as a plant cell fills (HL)

In a hypotonic solution, for example pure water (ψw = 0 kPa). The water potential outside (0) is higher than inside (−400), so water moves in. As the protoplast swells against the wall, ψp rises. The incoming water also dilutes the sap a little, so ψs becomes slightly less negative. Water keeps entering until ψw inside has risen to equal the outside, 0 kPa: the cell is fully turgid, with ψp roughly equal and opposite to ψs. The tissue gains mass and length. The wall stops the cell swelling further, so it never bursts.

In a hypertonic solution, for example ψw = −1000 kPa. The water potential outside is now lower than inside (−400), so water moves out. The protoplast shrinks and presses less on the wall, so ψp falls. When ψp reaches zero, the membrane is only just touching the wall; this is incipient plasmolysis, the point where ψw = ψs. Water is still leaving, because the cell's water potential, now a little below −700 kPa, is still higher than −1000. The protoplast pulls away from the wall (plasmolysis), ψp stays at zero, and the sap becomes more concentrated, so ψs falls until ψw inside equals −1000 kPa. The tissue loses mass and length.

In the practical, the isotonic concentration is the solution whose water potential equals the water potential of the tissue, so no net water moves.

13Where marks are lost

Describing direction in terms of water concentration. The guide wants solute concentration: water moves from lower to higher solute concentration, from hypotonic to hypertonic.

"In an isotonic solution no water moves." Water moves both ways at equal rates: dynamic equilibrium, no net movement.

Using hypotonic or hypertonic without saying compared with what. They are comparisons. Write "the solution is hypotonic to the cell".

"Plant cells burst in pure water." The wall resists expansion and turgor pressure stops further entry. Only cells without walls burst.

"In plasmolysis the cell wall shrinks." The wall stays where it is; the protoplast shrinks and the membrane pulls away from it.

Comparing absolute mass changes. Pieces start at different masses, so compare percentage changes.

HL · "−600 kPa is higher than −400 kPa." With negative numbers, the value closer to zero is higher. Water moves from −400 to −600.

HL · Giving solute potential a positive value, or pressure potential in a plasmolysed cell a negative one. ψs is zero or negative; ψp in a plasmolysed cell is zero. Negative ψp belongs to xylem under tension.

14Draw it right

  1. Solvation: water drawn with oxygen and two hydrogens; oxygens towards a positive ion, hydrogens towards a negative ion, and δ+ and δ− labelled.
  2. Red blood cells: swollen or burst in hypotonic, biconcave in isotonic, crenated in hypertonic, with the solution named in each case.
  3. Plant cells: the wall drawn thick and unchanged in all three; the membrane pressed against the wall (turgid), touching it (flaccid) or pulled away from it (plasmolysed).
  4. Graphs of tissue data: concentration on the x-axis with units; percentage change on the y-axis; a zero line; means plotted with error bars, and the isotonic point marked where the line crosses zero.
  5. HL values: every water potential written with its sign and its unit, kPa.

15Try it

Marks in brackets. Answers and marker's notes are at the end.

Q1. Red blood cells are placed in distilled water. What happens to them? 1 mark

A. They become turgid.

B. They crenate as water leaves.

C. They swell and burst as water enters.

D. There is no net movement of water.

Q2. Explain why a plant cell placed in pure water does not burst, whereas a red blood cell does. 3 marks

Q3. A student placed beetroot discs in sucrose solutions and recorded the mean percentage change in mass, with standard error, from eight discs per concentration. (Invented data.)

Sucrose / mol dm⁻³0.10.20.30.4
Mean change in mass / %+6.2+2.1−1.7−5.0
Standard error / %0.40.50.60.4

(a) Estimate the sucrose concentration that is isotonic with the beetroot tissue. Show your working. 2 marks

(b) Explain the change in mass at 0.4 mol dm⁻³. 2 marks

(c) State what the standard error tells you about the mean at each concentration. 1 mark

(d) Suggest why the student recorded percentage change rather than change in grams. 1 mark

Q4. Explain why a kidney removed for transplantation is stored in an isotonic solution. 2 marks

Q5 (HL). A potato cell has a solute potential of −750 kPa and a pressure potential of +250 kPa.

(a) Calculate the water potential of the cell. 1 mark

(b) The cell is placed in a solution with a water potential of −300 kPa. Predict and explain the direction of net water movement. 2 marks

(c) State the pressure potential of the cell at incipient plasmolysis. 1 mark

Q6 (HL). Explain, in terms of solute potential and pressure potential, the changes in a turgid plant cell placed in a hypertonic solution. 4 marks

16In one breath

Water dissolves ions and polar molecules because its δ− oxygens are attracted to positive ions, its δ+ hydrogens to negative ions, and it hydrogen-bonds with polar groups; each solute ends up in a shell of water. Water moves by osmosis from lower to higher solute concentration: from a hypotonic solution to a hypertonic one; in isotonic solutions it moves both ways equally, a dynamic equilibrium. Plant tissue in a range of solutions gains or loses length and mass; plot percentage change with standard-error bars, and the isotonic concentration is where the line crosses zero; SD measures the spread of repeats, SE how well the mean is known. Cells without walls burst in hypotonic and crenate in hypertonic solutions, so freshwater protists expel water with contractile vacuoles and animals keep tissue fluid isotonic. Cells with walls become turgid, not burst, in hypotonic solutions and plasmolyse in hypertonic ones. Intravenous fluids (such as 0.9% saline) and solutions for donor organs are isotonic so cells neither swell nor shrink. HL: water potential is the potential energy of water per unit volume, relative to pure water at atmospheric pressure and 20 °C (0 kPa), in kPa; water moves from higher (less negative) to lower; ψw = ψs + ψp, with ψs zero or negative and ψp usually positive in cells, zero at incipient plasmolysis, and negative in xylem under tension.


Answers

Q1. C. Distilled water is hypotonic to the cytoplasm, so water enters by osmosis; with no wall the cell swells and bursts. A needs a cell wall; B happens in hypertonic solutions. C only.

Q2. Pure water is hypotonic to the contents of both cells, so water enters both by osmosis. The plant cell has a cell wall, which resists expansion: as the protoplast swells, it presses on the wall and turgor pressure builds up, which stops further net entry of water, so the cell becomes turgid but does not burst. The red blood cell has no wall, so nothing resists the swelling and the membrane ruptures. 1 for water entering both by osmosis (hypotonic surroundings), 1 for the wall resisting expansion / turgor pressure, 1 for the red blood cell having no wall so it bursts.

Q3. (a) The change is zero between 0.2 and 0.3 mol dm⁻³. Interpolating: 0.2 + 0.1 × 2.1 ÷ (2.1 + 1.7) = 0.2 + 0.055 = 0.26 mol dm⁻³ (accept 0.25 to 0.26). M1 for recognising the zero crossing between 0.2 and 0.3 and a valid interpolation or graph reading, A1 for the value with unit. (b) The 0.4 mol dm⁻³ solution is hypertonic to the beetroot cells, so there is a net movement of water out of the cells by osmosis, reducing their mass. 1 for hypertonic / higher solute concentration outside, 1 for water leaving by osmosis. (c) How precisely the mean is known: small standard errors show the mean is a reliable estimate. [1.] (d) The discs had different starting masses, so percentage change allows fair comparison between them. [1.]

Q4. If the solution were hypotonic, water would enter the kidney's cells by osmosis and they could swell and burst; if hypertonic, water would leave and the cells would shrink. In an isotonic solution there is no net movement of water, so the cells keep their normal volume and are not damaged. 1 for the harm from either non-isotonic solution, 1 for no net movement in isotonic solution.

Q5 (HL). (a) ψw = −750 + 250 = −500 kPa. value with sign and unit. (b) Water moves into the cell, because the solution's water potential (−300 kPa) is higher than the cell's (−500 kPa), and water moves from higher to lower water potential. 1 for into the cell, 1 for the reason comparing the values. (c) 0 kPa. [1.]

Q6 (HL). The hypertonic solution has a lower (more negative) water potential than the cell, so water moves out of the cell by osmosis. As the protoplast shrinks, it presses less on the wall and the pressure potential falls, reaching zero at incipient plasmolysis. As water continues to leave, the cell sap becomes more concentrated, so the solute potential becomes more negative. The protoplast pulls away from the wall (plasmolysis) until the water potential of the cell equals that of the solution. 1 for lower water potential outside so water leaves, 1 for ψp falling to zero, 1 for ψs becoming more negative, 1 for plasmolysis continuing until the water potentials are equal. "ψp becomes negative" scores 0 for the second point.


Educerie · written from the published IB Diploma Programme Biology guide, first assessment 2025, section D2.3 Water potential. Original text, examples and questions. Diagrams drawn by Educerie. Last reviewed 25 September 2026.

Check your understanding

The main ideas of this note. Tick each one you could do now, in an exam, without looking back up. Anything you cannot tick yet is the part to read again.

Mocks: in the future, hold tight!