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Educerie · IB Diploma · Chemistry

Structure 1 Models of the particulate nature of matter · S1.2 The nuclear atom

Level
SL and HL. Section 6 is HL only. If you are SL, skip it; nothing in your papers tests it.
Themes (key concepts)
structure, and models that change with evidence. The nucleus is the part of the atom's structure that fixes which element it is and how heavy it is, and the nuclear atom itself is a model that replaced an older one when an experiment contradicted it.
The question this unit answers
how do the nuclei of atoms differ?
Where it is examined
Paper 1A, one-mark questions on the numbers of protons, neutrons and electrons in an atom or ion; Paper 2, a 2 to 3 mark calculation of relative atomic mass from isotope abundances, and short explanations of why isotopes behave alike chemically; HL Paper 1B and Paper 2, a mass spectrum to read and turn into a relative atomic mass.

What you must be able to do

You must be able toLevelWhat it looks like in the exam
Describe the nuclear atom: a small, dense, positive nucleus of protons and neutrons, with electrons outside itSL, HL"Describe the structure of an atom" (2 marks)
Give the relative masses and charges of the proton, neutron and electronSL, HLPaper 1A, or a table to complete (2 marks)
Use a nuclear symbol to deduce the numbers of protons, neutrons and electrons in atoms and ionsSL, HL"Deduce the number of neutrons and electrons in ⁵⁶Fe³⁺" (2 marks)
Define isotopes, and explain why they have the same chemical but different physical propertiesSL, HL"Explain why isotopes of an element have the same chemical properties" (2 marks)
Calculate a non-integer relative atomic mass from isotope masses and abundances, and work backwards to an abundanceSL, HLPaper 2, 2 to 3 marks, working shown
Interpret a mass spectrum: identify the isotopes, read their relative abundances, calculate Ar and identify the elementHL onlyPaper 1B or Paper 2 spectrum, 2 to 4 marks

Before you start

You need S1.1's idea that an element cannot be broken down chemically, and that matter is made of particles. You need to be happy with percentages and with multiplying a list of values by weights and adding them up. Have a copy of the data booklet open: its periodic table gives atomic numbers and relative atomic masses, and its table of fundamental constants gives the actual masses and charge of the subatomic particles.


1The idea in one paragraph

An atom is almost entirely empty space. At its centre is a nucleus, tens of thousands of times narrower than the atom but holding nearly all of its mass, made of positive protons and neutral neutrons. Around it, in the space that makes up the rest of the atom, are negative electrons. The number of protons decides which element an atom is. The number of neutrons can vary within one element, which gives isotopes: atoms that behave the same way chemically but have different masses. Because most elements are a mix of isotopes, the "mass of an atom" of an element is an average, the relative atomic mass, and that is why the numbers in the periodic table are not whole.

2Inside the atom

Figure 1 is a lithium-7 atom. It is not to scale, and cannot be: drawn with the nucleus the size shown, the atom would have to be hundreds of metres across.

Figure 1 · A lithium-7 atom, not to scale Figure 1 · A lithium-7 atom, not to scale nucleus: 3 protons, 4 neutrons positive, tiny, nearly all the mass 3 electrons, negative, in the space around it proton neutron electron A real atom is tens of thousands of times wider than its nucleus.
Figure 1 · A lithium-7 atom, not to scale

The three subatomic particles have these relative masses and charges. The data booklet gives their actual masses in kilograms and the actual charge in coulombs; what you must know is the relative values.

ParticleWhere it isRelative massRelative charge
Protonnucleus1+1
Neutronnucleus10
Electronoutside the nucleusabout 1/1836, taken as negligible−1

Protons and neutrons together are called nucleons. Because an electron's mass is about two-thousandths of a proton's, the mass of an atom is, to a very good approximation, the mass of its nucleons. That is why the nucleus is dense: nearly all the mass is squeezed into a tiny fraction of the volume.

An atom is neutral, so it has as many electrons as protons. The positive charge of the nucleus attracts the negative electrons, and that attraction is what holds an atom together. Almost all of chemistry is about the electrons, which are on the outside where other atoms can reach them. The nucleus is untouched by any chemical reaction.

How we know. Early in the twentieth century the accepted model spread the atom's positive charge evenly through it, with electrons embedded like fruit in a pudding. Figure 2 shows the experiment that ended it. A beam of fast, positive alpha particles was fired at a very thin sheet of gold.

Figure 2 · Why the nucleus must be small, dense and positive Figure 2 · Why the nucleus must be small, dense and positive beam of α particles (positive) thin gold foil most pass straight through → the atom is mostly empty space a few are deflected → they pass close to a positive charge a very few bounce back → they hit something tiny, massive and positive Only a tiny, concentrated positive charge could turn a fast positive particle round.
Figure 2 · Why the nucleus must be small, dense and positive

Nearly all the alpha particles went straight through, so most of the atom is empty space. A few were deflected, so there is concentrated positive charge somewhere in it. A very small number bounced back. Spread-out charge could never turn round a fast, heavy particle, so the positive charge and most of the mass had to be packed into something tiny. That something is the nucleus. The model was replaced because it could not explain the data, which is exactly how scientific models are supposed to change.

3The nuclear symbol

Every atom or ion can be written as a nuclear symbol. Figure 3 labels its parts.

Figure 3 · Reading a nuclear symbol Figure 3 · Reading a nuclear symbol Al 27 13 3+ mass number, A protons + neutrons atomic number, Z protons charge, if it is an ion 3+ means 3 electrons lost protons 13 neutrons 27 − 13 = 14 electrons 13 − 3 = 10 Top left is the mass number, bottom left the atomic number, top right the charge.
Figure 3 · Reading a nuclear symbol
  • The atomic number, Z, written bottom left, is the number of protons. It defines the element: every atom with 13 protons is aluminium, and the periodic table in the data booklet is arranged in order of Z.
  • The mass number, A, written top left, is the number of protons plus neutrons.
  • The charge, written top right, is present only for an ion.

In print it looks like ²⁷₁₃Al³⁺, and often the Z is left off, as in ²⁷Al³⁺, because the symbol Al already tells you Z = 13.

Three rules turn a symbol into numbers.

protons = Z · neutrons = A − Z · electrons = Z − charge

"Z − charge" handles both kinds of ion at once. A positive ion has lost electrons, so a charge of 3+ means 13 − 3 = 10 electrons. A negative ion has gained electrons, so a charge of 2− means you subtract −2, which adds 2. Losing or gaining electrons never changes the nucleus, so an ion has the same numbers of protons and neutrons as its atom.

SpeciesZAProtonsNeutronsElectrons
²⁷Al1327131413
²⁷Al³⁺1327131410
³²S²⁻1632161618
⁵⁶Fe²⁺2656263024
¹H⁺11100

The last row is worth a second look: a hydrogen-1 ion is a bare proton, with no neutron and no electron.

The rules also run backwards. A species with 17 protons, 20 neutrons and 18 electrons has Z = 17, which the periodic table says is chlorine, A = 17 + 20 = 37, and a charge of 17 − 18 = 1−. It is ³⁷Cl⁻.

4Isotopes

Isotopes are atoms of the same element with different numbers of neutrons. Same Z, different A. Figure 4 shows the two isotopes of chlorine found in nature.

Figure 4 · Two isotopes of chlorine Figure 4 · Two isotopes of chlorine chlorine-35 17 protons, 18 neutrons, 17 electrons chlorine-37 17 protons, 20 neutrons, 17 electrons same Z different A Same number of protons and electrons, so the same chemistry. Two more neutrons, so the heavier atom has different physical properties.
Figure 4 · Two isotopes of chlorine

Isotopes are named by their mass number: chlorine-35 and chlorine-37, or ³⁵Cl and ³⁷Cl.

Same chemical properties. Chemical reactions involve electrons. Isotopes of an element have the same number of protons, so the same number of electrons, arranged in the same way (S1.3 describes that arrangement). The extra neutrons are buried in the nucleus and take no part. So ³⁵Cl and ³⁷Cl form the same compounds, in the same ratios, in the same reactions. The linking question in the guide points ahead: the chemical properties of an atom are decided by its electrons, which is where S1.3 begins.

Different physical properties. Anything that depends on the mass of the atom differs. A heavier isotope, or a compound made from it, has a higher density, and in a gas its particles move more slowly at the same temperature (S1.1: same average kinetic energy, so a larger mass means a smaller speed), so it diffuses more slowly. Melting and boiling points differ slightly too. Water made with hydrogen-2 in place of hydrogen-1 is denser than ordinary water and boils a little above 100 °C. Some isotopes also have unstable nuclei and are radioactive, while others of the same element are stable. You do not need to learn named examples of isotopes; you need to explain the difference.

A useful consequence (it is a Nature of science link in the guide): because isotopes react identically but can be told apart by mass or by radioactivity, a chemist can build a reactant with one atom swapped for a rare isotope and then find where that labelled atom ends up in the products. These isotope tracers are one way reaction mechanisms are tested, which Reactivity 3.4 returns to.

5Relative atomic mass from isotopes

Most elements are a mixture of isotopes in fixed natural proportions. A sample of chlorine is about three-quarters ³⁵Cl and one quarter ³⁷Cl, so the average mass of a chlorine atom lies between 35 and 37, closer to 35. That average is the relative atomic mass, Ar: the weighted mean mass of the atoms of an element, on a scale on which one atom of carbon-12 has a mass of exactly 12 (S1.4 explains the scale). Because it is a ratio of masses, Ar has no units.

Ar = Σ (isotope mass × abundance) ÷ Σ (abundances)

When the abundances are percentages, the bottom line is 100. Exam questions usually give each isotope's mass as its mass number.

Worked example. Natural chlorine is 75.8% chlorine-35 and 24.2% chlorine-37.

Ar = (35 × 75.8 + 37 × 24.2) ÷ 100
= (2653 + 895.4) ÷ 100
= 35.48
= 35.5 (3 s.f.)

Figure 5 shows why the answer has to look like this. Think of the isotope masses as weights on a beam: the balance point is pulled towards the heavier weight, which here is the more abundant isotope.

Figure 5 · Relative atomic mass is a balance point Figure 5 · Relative atomic mass is a balance point 35 36 37 chlorine-35: 75.8% chlorine-37: 24.2% Ar ≈ 35.5 The balance point sits between the isotope masses, close to the more abundant one.
Figure 5 · Relative atomic mass is a balance point

Two checks catch most errors. The answer must lie between the smallest and largest isotope masses. And it must lie closer to the more abundant isotope. An answer of 36.0 for chlorine fails the second check straight away.

The data booklet gives chlorine's Ar as 35.45, not 35.48. The small difference is not an error in your method: real isotope masses are not exact whole numbers (chlorine-35 is slightly less than 35), and the booklet uses the precise values. In calculations from S1.4 onwards, always use the values in the data booklet, to two decimal places.

Working backwards to an abundance. If you know Ar and the isotope masses, you can find the abundances. For two isotopes, call the fraction of the lighter one x; the other is then 1 − x.

Boron has Ar = 10.81 and two isotopes, boron-10 and boron-11.

10x + 11(1 − x) = 10.81
10x + 11 − 11x = 10.81
11 − x = 10.81
x = 0.19fraction of boron-10
boron-10: 19%, boron-11: 81%

Check it against the balance point: 10.81 is much closer to 11 than to 10, so boron-11 must be the more abundant. It is.

6HLMass spectra

SL students can skip to section 7.

A mass spectrometer turns a sample of an element into positive ions and sorts them by mass. You will not be asked how the instrument works. You will be asked to read what it produces: a mass spectrum, a graph of how many ions arrive at each value of mass-to-charge ratio, m/z. For an element the ions carry a single positive charge, so m/z is simply the mass of each isotope, and every peak is one isotope. Figure 6 is the mass spectrum of magnesium.

Figure 6 · Mass spectrum of magnesium (HL) Figure 6 · Mass spectrum of magnesium (HL) Relative abundance (%) Mass-to-charge ratio, m/z 0 20 40 60 80 100 23 24 25 26 27 78.99 10.00 11.01 Three peaks, three isotopes. The tallest peak is the most abundant isotope.
Figure 6 · Mass spectrum of magnesium (HL)

Read it in three steps.

The number of peaks is the number of isotopes. Three peaks, so natural magnesium has three isotopes, with mass numbers 24, 25 and 26.

The height of each peak is its relative abundance. Magnesium-24 is 78.99% of the atoms, magnesium-25 is 10.00% and magnesium-26 is 11.01%.

Ar is the weighted mean of the peaks.

Ar = (24 × 78.99 + 25 × 10.00 + 26 × 11.01) ÷ 100
= (1895.76 + 250.00 + 286.26) ÷ 100
= 24.32

That agrees with the value of 24.31 in the data booklet to within the small difference from using mass numbers.

When the heights are not percentages. Many spectra give heights in arbitrary units, or as abundances scaled so the tallest peak is 100. Then the heights do not add up to 100, and you must divide by their actual total. An element gives two peaks: m/z 63 with height 9.2 and m/z 65 with height 4.1.

total height = 9.2 + 4.1 = 13.3
Ar = (63 × 9.2 + 65 × 4.1) ÷ 13.3
= (579.6 + 266.5) ÷ 13.3
= 846.1 ÷ 13.3
= 63.6

Dividing by 100 out of habit would give 8.46, which fails the "between the isotope masses" check at once.

Identifying the element. Find the element in the periodic table of the data booklet whose Ar is closest to your answer. 63.6 matches copper (63.55), and no other element is near it. When you "identify" an element this way, write both numbers down: yours and the booklet's.

Deducing neutrons from a peak. Each peak's m/z is a mass number, so once you know the element you can find the neutrons in each isotope: A − Z. In copper, Z = 29, so the isotope at 63 has 34 neutrons and the one at 65 has 36.

The guide's linking question looks ahead to Structure 3.2: a molecule in a mass spectrometer breaks into fragments, and the pattern of fragment peaks becomes evidence for its structure. For this subtopic, the sample is always a single element.

7Where marks are lost

Saying the mass number is the number of neutrons. A is protons plus neutrons. Neutrons are A − Z.

Getting the electrons in an ion the wrong way round. A positive ion has fewer electrons than protons, because it lost them. ⁵⁶Fe²⁺ has 24 electrons, not 28.

Saying isotopes have "the same properties". Same chemical properties, different physical ones. An answer that does not say which kind loses the mark.

Explaining the same chemistry with "same number of protons" alone. The reason is the same number and arrangement of electrons, because reactions involve electrons. Link protons to electrons, then electrons to chemistry.

Dividing by 100 when the abundances do not add up to 100. Divide by the total of the abundances you were given. (HL spectra do this often.)

Giving Ar a unit. Relative atomic mass is a ratio. "35.5 g" or "35.5 amu" is wrong; "35.5" is right. (Molar mass, in S1.4, does have a unit: g mol⁻¹.)

Quoting too many figures. If the abundances are given to three significant figures, your Ar should be too. 35.484 becomes 35.5.

8Draw it right

  1. An atom diagram shows a small central nucleus with protons and neutrons, and electrons outside it, with a key. Say "not to scale" if you draw one.
  2. Write a nuclear symbol with A top left, Z bottom left, charge top right, and the charge written as 2+ or 3−, number before sign.
  3. In a table of particles, the electron's relative mass is written as "negligible" or about 1/1836 (0.0005), never 0 and never 1.
  4. HL: when you sketch a mass spectrum, the horizontal axis is m/z and the vertical axis is relative abundance; each isotope is one vertical line at its mass number, and the heights are in the right ratio.
  5. HL: in a calculation from a spectrum, write the peak values you read off before you use them, so a misreading costs one mark and not all of them.

9Try it

Marks in brackets. Answers and marker's notes are at the end. Use the periodic table in the data booklet where you need Z or Ar.

Q1. How many protons, neutrons and electrons are in the ion ⁴⁰Ca²⁺? 1 mark

A. 20, 20, 22    B. 20, 20, 18    C. 20, 40, 18    D. 22, 18, 20

Q2. Complete the table. 4 marks

SpeciesProtonsNeutronsElectrons
³⁴S²⁻
⁵⁹Co³⁺
¹⁹F⁻
(to identify)263023

Q3. Chlorine-35 and chlorine-37 are isotopes. Explain why they have the same chemical properties, and state one physical property in which they differ. 3 marks

Q4. Natural neon contains 90.48% neon-20, 0.27% neon-21 and 9.25% neon-22. Calculate the relative atomic mass of neon to two decimal places. 2 marks

Q5. Gallium has two naturally occurring isotopes, gallium-69 and gallium-71, and a relative atomic mass of 69.72. Using mass numbers as the isotope masses, calculate the percentage abundance of gallium-69. 3 marks

Q6 (HL). Figure 7 is the mass spectrum of an element, E.

Figure 7 · Mass spectrum of element E (HL, Try it) Figure 7 · Mass spectrum of element E (HL, Try it) Relative abundance (%) Mass-to-charge ratio, m/z 0 20 40 60 80 100 83 84 85 86 87 88 89 0.56 9.86 7.00 82.58 Four isotopes of one element. Heights are percentage abundances.
Figure 7 · Mass spectrum of element E (HL, Try it)

(a) State the number of naturally occurring isotopes of E. 1 mark

(b) Calculate the relative atomic mass of E, and use the data booklet to identify E. 3 marks

(c) Deduce the number of neutrons in the most abundant isotope of E. 1 mark

10In one breath

An atom is a tiny, dense, positive nucleus of protons (mass 1, charge +1) and neutrons (mass 1, charge 0), surrounded by electrons (negligible mass, charge −1) in mostly empty space; alpha particles bouncing off gold foil showed the nucleus is small, massive and positive. Z is the number of protons and fixes the element, A is protons plus neutrons, neutrons are A − Z, and electrons are Z minus the charge, so positive ions have lost electrons and negative ions have gained them. Isotopes have the same Z and different A: same electrons so the same chemistry, different mass so different density, diffusion rate and boiling point. Relative atomic mass is the weighted mean of the isotope masses on the carbon-12 scale, has no units, lies between the isotope masses and nearest the most abundant one, and is found by multiplying each mass by its abundance, adding, and dividing by the total abundance. HL: a mass spectrum has one peak per isotope at m/z equal to its mass, peak height gives relative abundance, the weighted mean gives Ar, and the closest Ar in the data booklet identifies the element.


Answers

Q1. B. Z = 20 protons; 40 − 20 = 20 neutrons; a 2+ ion has lost two electrons, 20 − 2 = 18. B only. A is the classic error of adding electrons for a positive ion.

Q2.

SpeciesProtonsNeutronsElectrons
³⁴S²⁻161818
⁵⁹Co³⁺273224
¹⁹F⁻91010
⁵⁶Fe³⁺263023

1 for each correct row. For the last row, Z = 26 is iron, A = 26 + 30 = 56, charge = 26 − 23 = 3+; the symbol must carry all three to score.

Q3. Both isotopes have 17 protons and therefore 17 electrons, with the same electron arrangement. Chemical reactions involve the electrons, so the two isotopes react in the same way. They differ in mass (chlorine-37 has two more neutrons), so any property that depends on mass differs: for example the density of the gas, its rate of diffusion, or its boiling point. 1 for same number (and arrangement) of electrons, 1 for chemical properties depending on electrons, 1 for a correct physical property linked to mass. "They have the same number of protons" alone scores 0 for the first mark: the link to electrons is the point.

Q4.

Ar = (20 × 90.48 + 21 × 0.27 + 22 × 9.25) ÷ 100
= (1809.6 + 5.67 + 203.5) ÷ 100
= 20.19

M1 for the weighted sum divided by 100, A1 for 20.19. 20.2 is accepted for A1 only if the question did not ask for two decimal places; here it did.

Q5. Let the fraction of gallium-69 be x.

69x + 71(1 − x) = 69.72
71 − 2x = 69.72
x = 0.64
gallium-69 = 64%

M1 for setting up the weighted mean with x and 1 − x (or percentages summing to 100), M1 for correct rearrangement, A1 for 64%. Check: 69.72 is nearer 69, so gallium-69 should be the more abundant, and it is. Using exact isotope masses the real figure is about 60%; the question fixes the method, so 64% is the answer.

Q6 (HL). (a) Four isotopes (four peaks). [1] (b)

Ar = (84 × 0.56 + 86 × 9.86 + 87 × 7.00 + 88 × 82.58) ÷ 100
= (47.04 + 847.96 + 609.00 + 7267.04) ÷ 100
= 87.71

The closest relative atomic mass in the data booklet is strontium's, 87.62, so E is strontium. M1 for the weighted mean with the four peaks read correctly, A1 for 87.71 (accept 87.7), A1 for strontium with a reason. Rubidium (85.47) and yttrium (88.91) are both too far away. (c) Strontium has Z = 38. The most abundant isotope is at m/z 88, so it has 88 − 38 = 50 neutrons. accept an answer carried forward from a wrong identification in (b) if A − Z is applied correctly.


Educerie · written from the published IB Diploma Programme Chemistry guide, first assessment 2025, section S1.2 The nuclear atom. Original text, examples and questions. Diagrams drawn by Educerie. Last reviewed 25 September 2026.

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