Educerie
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Educerie · IB Diploma · Mathematics: analysis and approaches

Topic 1 Number and algebra · 1.1 Scientific notation

Level
SL and HL. Nothing here is HL only, so every section is examinable for both.
Themes (key concepts)
representation, quantity, equivalence. A number written as a × 10ᵏ is the same quantity in a different representation, and that representation makes very large and very small numbers easy to compare and to calculate with.
The question this unit answers
how do you write, compare and calculate with numbers far too large or too small to write out in full?
Where it is examined
Paper 1 section A, as a 2 to 4 mark question done by hand, or as the last line of a longer question; Paper 2, wherever a calculator answer is very large or very small and the question says "give your answer in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ".

What you must be able to do

You must be able toLevelWhat it looks like in the exam
Write any number in the form a × 10ᵏ, and convert backSL, HL"Write 0.000 0482 in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ" (1 to 2 marks)
Compare and order numbers written in this formSL, HLA list to put in order, or "which is larger" inside a context question
Multiply, divide, square and square-root in this form without a calculatorSL, HLPaper 1: "Find the value of (6 × 10⁴)(5 × 10⁻⁹), giving your answer in the form…" (2 to 3 marks)
Add and subtract in this form without a calculatorSL, HLPaper 1: "Find 3.2 × 10⁵ + 4 × 10⁴…" (2 marks)
Turn a calculator display into correct notation, rounded as askedSL, HLPaper 2: any answer the GDC shows as 4.73E18. Writing the E loses the mark

Before you start

You need powers of ten: 10³ = 1000, 10¹ = 10, 10⁰ = 1, 10⁻¹ = 0.1, 10⁻³ = 0.001. A negative power of ten is one divided by that power, which 1.5 explains properly. You also need rounding to a given number of significant figures, from your earlier study.


1The idea in one paragraph

Some numbers have too many zeros to write sensibly: the distance from the Earth to the Sun is about 150 000 000 000 metres, and an atom is about 0.000 000 000 1 metres across. Scientific notation writes every positive number as a number between 1 and 10 multiplied by a power of ten: 1.5 × 10¹¹ and 1 × 10⁻¹⁰. The first part carries the digits and the power carries the size. Because the power does the counting, you can see at a glance which of two numbers is bigger, and you can multiply and divide by working with the two parts separately.

2What the form means

A number is in the form a × 10ᵏ when two conditions hold.

a × 10ᵏ, where 1 ≤ a < 10 and k is an integer (k ∈ ℤ)

a has exactly one non-zero digit before the decimal point. So 3.844, 1 and 9.99 are allowed; 38.44, 0.3844 and 10 are not. k is a whole number, positive, negative or zero. Figure 1 labels the two parts.

Figure 1 · The two parts of a number in the form a × 10ᵏ Figure 1 · The two parts of a number in the form a × 10ᵏ 3.844 × 10 5 a, with 1 ≤ a < 10 exactly one non-zero digit before the decimal point k, an integer k > 0: the number is 10 or more k < 0: the number is less than 1 k = 0: from 1 up to 10 3.844 × 10⁵ = 384 400. The a carries the digits, the k carries the size.
Figure 1 · The two parts of a number in the form a × 10ᵏ

The sign of k tells you the size at once:

k isthe number isexample
positive10 or more3.844 × 10⁵ = 384 400
zerofrom 1 up to (not including) 107.2 × 10⁰ = 7.2
negativeless than 17.5 × 10⁻⁷ = 0.000 000 75

Why insist on 1 ≤ a < 10? Because it makes the form unique. The number 384 400 could be written as 38.44 × 10⁴ or 0.3844 × 10⁶, and both are true, but only 3.844 × 10⁵ is in the form. One number, one way of writing it, and that is what lets you compare numbers by looking at k.

A negative number keeps its minus sign in front: −0.000 62 = −6.2 × 10⁻⁴. The condition applies to the size of a.

Figure 2 shows why this form is so useful. Each tick on the ruler is ten times the one before, so lengths from an atom to a light year fit on one line. The power k tells you which step a length sits in; a tells you where inside that step.

Figure 2 · Lengths from an atom to a light year, one step per power of ten Figure 2 · Lengths from an atom to a light year, one step per power of ten 10⁻¹⁰ 10⁻⁸ 10⁻⁶ 10⁻⁴ 10⁻² 10⁰ 10² 10⁴ 10⁶ 10⁸ 10¹⁰ 10¹² 10¹⁴ 10¹⁶ metres an atom 1.0 × 10⁻¹⁰ m a red blood cell 8.0 × 10⁻⁶ m a person 1.7 × 10⁰ m Mount Everest 8.8 × 10³ m Earth's diameter 1.3 × 10⁷ m Earth to Moon 3.8 × 10⁸ m Earth to Sun 1.5 × 10¹¹ m one light year 9.5 × 10¹⁵ m Each tick multiplies by ten. The power k says which step a length is in; a says where inside it.
Figure 2 · Lengths from an atom to a light year, one step per power of ten

The figure uses real, rounded values: an atom is about 1 × 10⁻¹⁰ m across, the mean distance from the Earth to the Sun is about 1.5 × 10¹¹ m, and a light year is about 9.5 × 10¹⁵ m. Some numbers are famous enough to have names of their own: a googol is 10¹⁰⁰. Most never get one, and a × 10ᵏ is how they are written instead.

3Converting into the form, and back

Into the form. Move the decimal point until it sits just after the first non-zero digit, and count how many places it moved. That count is the size of k. The direction gives the sign: a number bigger than 10 needs a positive k, a number less than 1 needs a negative k. Figure 3 shows both cases hop by hop.

Figure 3 · Counting the places the decimal point moves Figure 3 · Counting the places the decimal point moves Large number: 384 400 km, the mean distance from Earth to the Moon 3 8 4 4 0 0 → 3.844 × 10⁵ The point hops 5 places left, from the clay dot to just after the first digit, so k = +5. Small number: 0.000 000 75 m, about the wavelength of red light 0 0 0 0 0 0 0 7 5 → 7.5 × 10⁻⁷ The point hops 7 places right, to just after the first non-zero digit, so k = −7. Big numbers get a positive k, numbers below 1 a negative k. Count the hops, not the zeros.
Figure 3 · Counting the places the decimal point moves
384 400 = 3.844 × 105point moves 5 places left: number is large, k = +5
0.000 000 75 = 7.5 × 10-7point moves 7 places right: number is small, k = −7
6 020 000 = 6.02 × 106
0.0409 = 4.09 × 10-2

Check each answer by asking "is it big or small?" before you write the sign of k. That one question catches most slips.

Back to an ordinary number. Run the process backwards: a positive k moves the point k places right, a negative k moves it k places left, filling empty places with zeros.

2.07 × 104 = 20 700
5.3 × 10-3 = 0.0053

Fixing a number that is almost in the form. Questions often produce something like 42 × 10⁵ or 0.6 × 10⁻³ halfway through a calculation. Rewrite a, and let the power absorb the change. Making a ten times smaller means making the power ten times bigger, so k goes up by 1; making a ten times bigger sends k down by 1.

42 × 105 = 4.2 × 101 × 105 = 4.2 × 106a divided by 10, k up by 1
0.6 × 10-3 = 6 × 10-1 × 10-3 = 6 × 10-4a multiplied by 10, k down by 1

Writing the middle step, 4.2 × 10¹ × 10⁵, is the safe way to do this. It shows the examiner your method and it stops you moving k the wrong way.

4Comparing and ordering

For positive numbers in the form, compare k first. A larger k always means a larger number, whatever the a's are, because a can never reach 10. Only if the k's are equal do you compare the a's.

Put these in order, smallest first: 9.9 × 10⁻⁴, 1.2 × 10⁻³, 8.5 × 10⁻⁴, 3 × 10⁻⁵.

The powers are −4, −3, −4 and −5. The smallest power is −5, so 3 × 10⁻⁵ comes first. The two with k = −4 are ordered by a: 8.5 before 9.9. The largest power, −3, comes last.

3 × 10⁻⁵ < 8.5 × 10⁻⁴ < 9.9 × 10⁻⁴ < 1.2 × 10⁻³

Notice that 9.9 × 10⁻⁴ is smaller than 1.2 × 10⁻³ even though 9.9 is bigger than 1.2. With negative powers, remember that −3 is bigger than −4. Write them out as decimals once if you doubt it: 0.000 99 against 0.0012.

5Multiplying, dividing, powers and roots

Multiplication does not care about order, so you can collect the a's together and the powers of ten together. Figure 4 sets out the route on its left side: work with the a's, then with the powers, then tidy up.

Figure 4 · Two kinds of operation, two routes Figure 4 · Two kinds of operation, two routes Multiply or divide Add or subtract 1 · Work with the a's multiply or divide them 1 · Match the powers rewrite one number so both have the same k 2 · Work with the powers add the k's (×) or subtract them (÷) 2 · Add or subtract the a's keep the shared power of 10 3 · Tidy up if a is not between 1 and 10, move the point and adjust k 3 · Tidy up if a is not between 1 and 10, move the point and adjust k (4 × 10⁵) × (6 × 10⁸) = 24 × 10¹³ = 2.4 × 10¹⁴ 5.2 × 10⁶ + 3.1 × 10⁵ = 5.2 × 10⁶ + 0.31 × 10⁶ = 5.51 × 10⁶ Powers of ten combine only under × and ÷. Under + and − they must match first.
Figure 4 · Two kinds of operation, two routes

The power-of-ten step uses the laws you will meet formally in 1.5: multiplying adds the powers, dividing subtracts them.

(4 × 105) × (6 × 108)
= (4 × 6) × 105 + 8a's together, powers together
= 24 × 1013
= 2.4 × 1014a was too big: divide it by 10, k up by 1
(3 × 10-4) ÷ (6 × 105)
= (3 ÷ 6) × 10−4 − 5
= 0.5 × 10-9
= 5 × 10-10a was too small: multiply it by 10, k down by 1

The tidy-up step is where the final mark sits. An answer of 24 × 10¹³ is correct in value but not in the form asked for, and it loses the accuracy mark.

Powers. Raise both parts to the power, remembering that (10ᵏ)ⁿ = 10ᵏⁿ.

(3 × 104)2 = 32 × 108 = 9 × 108
(2 × 10-3)3 = 23 × 10-9 = 8 × 10-9
(5 × 106)2 = 25 × 1012 = 2.5 × 1013

Square roots. The square root of 10ᵏ is a whole power of ten only when k is even. So first rewrite the number with an even power, then take the root of each part.

√(1.6 × 109)
= √(16 × 108)make the power even: a × 10, k − 1
= √16 × √(108)
= 4 × 104

On Paper 1 the numbers are chosen so this comes out cleanly. If it does not, check whether you moved k the right way.

6Adding and subtracting

Here the powers cannot simply be combined. 5 × 10⁶ + 3 × 10⁵ is not 8 × 10¹¹ or 8 × 10⁶; the two numbers are counting in different-sized units. Follow the right side of Figure 4: rewrite one number so both have the same power of ten, then add or subtract the a's, then tidy up.

5.2 × 106 + 3.1 × 105
= 5.2 × 106 + 0.31 × 106rewrite the smaller one with k = 6
= 5.51 × 106
7 × 10-3 − 4 × 10-4
= 70 × 10-4 − 4 × 10-4rewrite the first with k = −4
= 66 × 10-4
= 6.6 × 10-3tidy: a divided by 10, k up by 1

Either number can be the one you rewrite. Rewriting the smaller one to match the larger one usually saves the tidy-up step. If the two powers are far apart, the smaller number may barely change the answer: 4 × 10⁹ + 3 × 10² = 4.000 000 3 × 10⁹, which is 4.00 × 10⁹ to three significant figures.

7With a calculator: Paper 2

A GDC works in this form happily, but it displays it in its own shorthand. 4.73E18 on the screen means 4.73 × 10¹⁸. That shorthand is calculator notation, and the IB does not accept it as an answer. Figure 5 shows the translation you must make every time.

Figure 5 · What the calculator shows, and what you write Figure 5 · What the calculator shows, and what you write GDC screen 4.73E18 ✗ not acceptable on the paper your answer 4.73 × 10¹⁸ ✓ mathematical notation The E is the calculator's shorthand for × 10 to the power. Translate it before you write it down.
Figure 5 · What the calculator shows, and what you write

Three habits make Paper 2 calculations safe.

Enter the number with the calculator's own ×10ⁿ key (labelled EE or ×10ˣ, depending on the model) rather than typing × 10 ^. The key keeps the number together as one value, so a division by 6.02 × 10²³ divides by the whole number, not by 6.02 and then multiplies by 10²³.

Keep full accuracy until the end. Store intermediate values in the memory; round only the final answer.

Round a, not the whole number. "Three significant figures" in this form means three digits in a: 6.923 076… × 10⁹ becomes 6.92 × 10⁹. The IB's default, when a question does not say otherwise, is an exact answer or three significant figures.

Two worked examples with real, rounded constants from physics and chemistry.

How long does light take to reach us from the Sun? The mean Earth–Sun distance is about 1.496 × 10¹¹ m and the speed of light is about 2.998 × 10⁸ m s⁻¹.

time = distance ÷ speed
= (1.496 × 1011) ÷ (2.998 × 108)
= 499.0 sGDC gives 498.999…
= 4.99 × 102 sabout 8.3 minutes

What is the mass of one carbon-12 atom? A mole of carbon-12 has mass 12 g and contains about 6.022 × 10²³ atoms (the Avogadro constant, which you will meet in chemistry).

mass of one atom = 12 ÷ (6.022 × 1023)
= 1.99269… × 10-23 gGDC shows 1.99269E-23
= 1.99 × 10-23 ga rounded to 3 s.f.

Physics also talks about the order of magnitude of a quantity: the power of ten it is nearest to. A light year, 9.5 × 10¹⁵ m, is of order 10¹⁶ m. That is a useful estimate and a quick check on any calculator answer: if the Sun's light seemed to take 10⁻³ seconds to arrive, something was typed wrongly.

8Where marks are lost

Leaving a outside 1 ≤ a < 10. 24 × 10¹³ and 0.5 × 10⁻⁹ have the right value and the wrong form. When the question specifies the form, the final accuracy mark needs it.

Moving k the wrong way when tidying. Making a smaller makes k bigger. Write the middle step, 2.4 × 10¹ × 10¹³, and the direction takes care of itself.

Getting the sign of k backwards. 0.0409 is small, so its k is negative. Ask "big or small?" before you write the power.

Counting zeros instead of places. 384 400 has two zeros but the point moves five places; 0.0409 has three zeros but the point moves two. Count the hops the point makes, as in Figure 3.

Adding powers under addition. 5 × 10⁶ + 3 × 10⁵ is not 8 × 10¹¹. Powers of ten add only when you multiply.

Writing calculator notation. 4.73E18 scores zero as a final answer. Write 4.73 × 10¹⁸.

Comparing a's before k's. 9.9 × 10⁻⁴ is less than 1.2 × 10⁻³. The power decides first.

Rounding too early. Rounding 1.496 ÷ 2.998 to 0.50 before dealing with the powers gives 500 s rather than 499 s, and the final answer to 3 s.f. is wrong.

9Work it right

  1. Read the form the question asks for, and copy the condition: 1 ≤ a < 10, k ∈ ℤ.
  2. Converting: move the point to just after the first non-zero digit, count the places, and give k the sign that matches "big" or "small".
  3. Multiplying or dividing: a's together, powers together, then tidy.
  4. Adding or subtracting: match the powers first, then combine the a's, then tidy.
  5. Tidy with a written middle step, so k moves the right way.
  6. On Paper 2, enter numbers with the ×10ⁿ key, keep full accuracy, round a at the end, and translate any E before you write the answer.
  7. Sense-check the size: is the answer big or small, and is its order of magnitude believable?

10Try it

Marks in brackets. Questions 1 to 3 are Paper 1 style: no calculator. Questions 4 and 5 are Paper 2 style, except where a part says otherwise.

Q1.

(a) Write 0.000 060 7 in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ. 1 mark

(b) Write 3.9 × 10⁴ as an ordinary number. 1 mark

Q2. Without using a calculator, find the value of (8 × 10⁷) × (3 × 10⁻²) ÷ (4 × 10³), giving your answer in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ. 3 marks

Q3. Without using a calculator, find 4.8 × 10⁵ − 6 × 10⁴, giving your answer in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ. 2 marks

Q4. A lorry carries 1.8 × 10⁴ kg of fine sand. Take the mass of one grain of this sand to be 2.6 × 10⁻⁶ kg (an invented figure for this question).

(a) Find the number of grains in the load. Give your answer in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ, correct to three significant figures. 2 marks

(b) Each grain is 3 × 10⁻⁴ m long. The grains are laid end to end in a single line. Find the length of the line in kilometres, giving your answer in the form a × 10ᵏ, where 1 ≤ a < 10 and k ∈ ℤ. 3 marks

Q5. Let x = 5 × 10ᵐ and y = 2 × 10ⁿ, where m and n are integers. Do not use a calculator.

(a) Write xy in the form a × 10ᵏ, where 1 ≤ a < 10, giving k in terms of m and n. 2 marks

(b) Write x ÷ y in the form a × 10ᵏ, where 1 ≤ a < 10, giving k in terms of m and n. 1 mark

(c) Given that xy = 1 × 10⁷ and m − n = 2, find the value of m and the value of n. 3 marks

11In one breath

Scientific notation writes a number as a × 10ᵏ with 1 ≤ a < 10 and k an integer, so a carries the digits and k carries the size; a positive k means 10 or more, a negative k means less than 1, and the form is unique, which is why you compare k first and a second. To convert, move the point to just after the first non-zero digit and count the places. To multiply or divide, handle the a's and the powers separately, adding or subtracting the k's, then tidy a back into the range with a written middle step: making a smaller makes k bigger. To add or subtract, match the powers first. For a square root, make the power even. On Paper 2, use the ×10ⁿ key, keep full accuracy, round a at the end, and never write the calculator's E.


Answers

Q1. (a) The point moves 5 places right to land after the 6, and the number is small, so 6.07 × 10⁻⁵. (b) The point moves 4 places right: 39 000. A1 for (a), A1 for (b). In (a), 60.7 × 10⁻⁶ or 6.07 × 10⁵ scores zero.

Q2.

(8 × 107) × (3 × 10-2) = 24 × 105
24 × 105 ÷ (4 × 103) = 6 × 105 − 3
= 6 × 102

M1 for multiplying the a's and adding the powers (or any correct combination of the three numbers), M1 for dividing by 4 and subtracting 3 from the power, A1 for 6 × 10². An answer of 600 scores M1 M1 A0, because it is not in the form asked for.

Q3.

4.8 × 105 − 0.6 × 105match the powers
= 4.2 × 105

M1 for writing both numbers with the same power of ten (48 × 10⁴ − 6 × 10⁴ is equally good), A1 for 4.2 × 10⁵. Subtracting a's and powers separately, as in −1.2 × 10¹, scores zero.

Q4. (a)

number of grains = (1.8 × 104) ÷ (2.6 × 10-6)
= 6.923 07… × 109
= 6.92 × 109

(b)

length = 6.923 07… × 109 × 3 × 10-4use the unrounded value from (a)
= 2.076 92… × 106 m
= 2.076 92… × 103 kmdivide by 1000
= 2.08 × 103 km

(a) M1 for dividing total mass by the mass of one grain, A1 for 6.92 × 10⁹. (b) M1 for multiplying the number of grains by the length of one, M1 for converting metres to kilometres by dividing by 10³, A1 for 2.08 × 10³ km. Follow through from (a) in (b). An answer written 6.92E9 loses the A1 in (a).

Q5. (a) xy = 5 × 2 × 10ᵐ⁺ⁿ = 10 × 10ᵐ⁺ⁿ = 1 × 10ᵐ⁺ⁿ⁺¹. (b) x ÷ y = (5 ÷ 2) × 10ᵐ⁻ⁿ = 2.5 × 10ᵐ⁻ⁿ. (c) From (a), m + n + 1 = 7, so m + n = 6. With m − n = 2, adding gives 2m = 8, so m = 4 and n = 2. Check: x = 5 × 10⁴ and y = 2 × 10², so xy = 10 × 10⁶ = 1 × 10⁷. ✓ (a) M1 for 10 × 10ᵐ⁺ⁿ, A1 for 1 × 10ᵐ⁺ⁿ⁺¹. (b) A1 for 2.5 × 10ᵐ⁻ⁿ. (c) M1 for m + n + 1 = 7 (follow through from their (a)), M1 for solving the pair of equations, A1 for both values. The answer 10 × 10ᵐ⁺ⁿ in (a) is not in the form and loses the A1.


Educerie · written from the published IB Diploma Programme Mathematics: analysis and approaches guide, first assessment 2021, section 1.1 Scientific notation. Original text, examples and questions. Diagrams drawn by Educerie. Last reviewed 25 September 2026.

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