Educerie

Educerie · SAT · Math

Advanced Math · ADV.3 Nonlinear functions

Where it is examined
both modules. The interpretation half of Advanced Math, and the place where exponential models appear.
The question this unit answers
a parabola or a growth curve, and a question about what it means rather than where it crosses. What does each number in the function do?
Before you start
equivalent expressions — particularly the three forms of a quadratic — and linear functions, because an exponential is defined by the way it differs from one.

What you must be able to do

You must be able toWhat it looks like on the test
Read a parabola's vertex, zeros and intercept from its form…which form displays the minimum as a constant?
Interpret a quadratic model in contextMaximum height, time to land, break-even
Write and read an exponential model…increases by 6% each year
Tell linear from exponentialSame amount each step, or same factor
Handle transformationsf(x) + 3, f(x − 2), −f(x), 2f(x)

1The idea in one paragraph

A nonlinear function is still a machine with an input and an output, and the test asks the same three things it asks about lines: where it starts, how it changes, and where it is highest or lowest. For a parabola that means the vertex; for an exponential it means the multiplier. Everything else in this unit follows from knowing which form of the function shows you which fact.

A quadratic's vertex sits exactly halfway between its zeros. If you can factor it, you can find its maximum without completing anything.

2The three forms, and what each displays

FormWrittenDisplays
Standardy = ax² + bx + cThe y-intercept, c
Factoredy = a(x − r)(x − s)The zeros, r and s
Vertexy = a(x − h)² + kThe vertex, (h, k)

The sign of a says which way it opens: positive opens upwards and has a minimum, negative opens downwards and has a maximum.

The vertex's x-coordinate is −b/2a in standard form, or the midpoint of the zeros in factored form. A question asking for "the maximum value" wants k — the y-coordinate — while one asking "at what time is the height greatest" wants h.

3Quadratics in context

h(t) = −5t² + 20t + 1 gives the height of a ball in metres after t seconds.

h(0) = 1the launch height
t = −b/2a = −20/(2 × −5) = 2when it is highest
h(2) = −5(4) + 40 + 1 = 21how high it gets
−5t2 + 20t + 1 = 0when it lands

Read the units in the question to know which of those three it wants. "How long until it lands" is a zero; "how high does it get" is the vertex's y; "when is it highest" is the vertex's x.

4Exponential functions

y = a · bˣ: a is the starting value, b is the multiplier per step.

Englishb
grows 8% a year1.08
falls 12% a year0.88
doubles each hour2
halves every 6 hours0.5, with exponent t/6
start = 4000
grows 3% a year → b = 1.03
P(t) = 4000(1.03)t

The most common wrong answer writes 0.03 as the multiplier, which would destroy 97% of the population each year.

When the period differs from the unit — halving every 6 hours, with t in hours — the exponent becomes t/6.

5Telling linear from exponential

Look at a table. Equal differences between successive outputs means linear; equal ratios means exponential.

x0123
f(x)5102040
differences: 10 − 5 = 5, 20 − 10 = 10not constant, so not linear
ratios: 10/5 = 2, 20/10 = 2, 40/20 = 2constant, so exponential
f(x) = 5 × 2x

In words: a quantity that grows by a fixed amount is linear, and one that grows by a fixed percentage is exponential. The phrase "per year" appears in both, so read what follows it.

6Transformations

WrittenDoes
f(x) + kMoves up k
f(x) − kMoves down k
f(x − h)Moves right h
f(x + h)Moves left h
−f(x)Reflects in the x-axis
a·f(x)Stretches vertically by a

The horizontal ones run opposite to their sign, which is the whole difficulty. f(x − 3) moves right, not left.


Where points are lost

  • Writing 0.06 instead of 1.06 for 6% growth.
  • Reporting h when the question wants k, or the reverse.
  • Getting the direction of a horizontal shift backwards.
  • Assuming linear because the table's inputs are evenly spaced.
  • Forgetting that a < 0 means a maximum, not a minimum.
  • Using the wrong zero for a landing time — negative times are not answers.
  • Missing the /6 when the halving period is not one unit.

Work it right

  1. Decide the family: is it a parabola or a growth curve?
  2. For a parabola, find the form you have and the fact you need.
  3. For an exponential, name a and b before anything else.
  4. Check the sign of a, and whether the question wants when or how much.
  5. Graph it to confirm, if the calculator is quicker than the algebra.

Try it

Q1. The function h(t) = −5t² + 30t gives the height, in metres, of a projectile t seconds after launch. What is its maximum height, in metres? (Type your answer.)

Q2. A colony of 900 bacteria grows by 15% every hour. Which function gives the population after t hours?

A) P(t) = 900(0.15)ᵗ B) P(t) = 900(1.15)ᵗ C) P(t) = 900 + 1.15t D) P(t) = 900(15)ᵗ

Q3. The function f is defined by f(x) = (x − 4)(x + 2). What is the x-coordinate of the vertex of its graph?

A) −2 B) 1 C) 2 D) 4

Q4. A sample of 240 g of an isotope halves every 8 days. Which function gives the mass after d days?

A) m(d) = 240(0.5)^(8d) B) m(d) = 240(0.5)^(d/8) C) m(d) = 240(8)^(d/2) D) m(d) = 240 − 0.5d

Q5. The graph of y = g(x) is shifted 3 units right and 2 units down. Which function describes the result?

A) g(x + 3) − 2 B) g(x − 3) − 2 C) g(x − 3) + 2 D) g(x + 3) + 2

In one breath

A parabola's three forms each display one fact — standard gives the y-intercept, factored gives the zeros, vertex form gives the turning point — and the vertex always sits halfway between the zeros. An exponential is a starting value times a multiplier: 6% growth is 1.06, not 0.06, and a half-life of six hours puts t/6 in the exponent. Equal differences in a table mean linear, equal ratios mean exponential, and horizontal shifts always run opposite to their sign.

Answers

Q1. 45. vertex at t = −b/2a, then evaluate

t = −30 / (2 × −5) = 3
h(3) = −5(9) + 30(3)
h(3) = −45 + 90 = 45

Answering 3 gives the time rather than the height, which is the split this question tests.

Q2. B. 15% growth means a multiplier of 1.15 A would leave 15% of the colony each hour. C is linear growth. D multiplies by 15 every hour.

Q3. B — 1. midpoint of the zeros

f(x) = (x − 4)(x + 2)
zeros at x = 4 and x = −2
vertex x = (4 + (−2)) / 2 = 1

A and D are the zeros themselves. C is their sum.

Q4. B. the halving period goes under t

m(d) = 240(0.5)^(d/8)
m(8) = 240(0.5)1 = 120halved once after 8 days
m(16) = 240(0.5)2 = 60

A halves every 1/8 of a day. C grows. D is linear decay, which never reaches a half-life.

Q5. B — g(x − 3) − 2. horizontal shifts run opposite to their sign Right is minus inside; down is minus outside. A shifts left. C and D move up.


Educerie · written from the published College Board* Assessment Framework for the Digital SAT Suite *(Math, Advanced Math, skill/knowledge testing point "Nonlinear functions"). All questions and explanations are original Educerie text. Last reviewed 12 September 2026.

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