Educerie
Level

Educerie · IB Diploma · Biology

Theme B Form and function · B1.1 Carbohydrates and lipids

Level
SL and HL. Nothing here is HL only, so every section is examinable for both.
Themes (key concepts)
form and function, at the level of molecules. Theme B says that forms correspond to functions, and this subtopic is the smallest scale at which you can watch that happen: flip one –OH group on glucose and you turn a food store into a plant's skeleton; add one double bond to a fatty acid and a solid fat becomes an oil.
The question this unit answers
in what ways do variations in form allow diversity of function in carbohydrates and lipids, and how do the two compare as energy stores?
Where it is examined
Paper 1A multiple choice, where you identify a pentose, a hexose or a steroid from a structural diagram, or pick the reaction that releases water; Paper 1B and Paper 2 Section A data questions, typically melting points against double bonds or energy content per gram; Paper 2 short answers (draw α-glucose, outline the role of glycoproteins, 2–4 marks); and Paper 2 Section B, where "compare carbohydrates and lipids as energy stores" or "explain how the structure of cellulose suits its function" is a natural 4–6 mark part of a longer question.

What you must be able to do

You must be able toLevelWhat it looks like in the exam
Explain why carbon can form the diverse compounds life is built on, including chains, branches and ringsSL, HL"Outline the properties of carbon that allow…" (2–3 marks)
Use the SI prefixes kilo, centi, milli, micro and nano correctlySL, HLUnit conversions inside any data question
Describe condensation and hydrolysis, with examples of the three kinds of polymerSL, HL"Distinguish between condensation and hydrolysis" (2 marks); multiple choice on which reaction releases water
Recognise pentoses and hexoses from ring diagramsSL, HLPaper 1A: "Which molecule is a hexose?" with four diagrams
Relate the properties of glucose to its usesSL, HL"Explain how the properties of glucose suit it to transport in the blood" (3 marks)
Explain how starch and glycogen are suited to energy storageSL, HL"Compare starch and glycogen" (3 marks) or part of an extended response
Relate the structure of cellulose to its functionSL, HL"Explain how the structure of cellulose is related to its function" (4 marks)
Outline the role of glycoproteins in cell–cell recognition, using ABO antigensSL, HL"Outline the basis of the ABO blood groups" (3 marks)
Define a lipid by its solubilitySL, HLOne-mark definition, or a multiple-choice distractor
Describe how triglycerides and phospholipids form by condensationSL, HL"State the number of water molecules released when…" (1 mark); draw and label
Distinguish saturated, monounsaturated and polyunsaturated fatty acids and link them to melting pointSL, HLPaper 1B data on melting points (3–5 marks)
Explain why triglycerides suit long-term energy storage and thermal insulationSL, HL"Compare carbohydrates and lipids as energy stores" (4–6 marks)
Explain bilayer formation using the term amphipathicSL, HL"Explain why phospholipids form bilayers in water" (3 marks)
Identify steroids from diagrams and explain why they cross membranesSL, HLPaper 1A identification; "Explain how testosterone enters a target cell" (2 marks)

Before you start

You need A1.1 Water: water is polar, it forms hydrogen bonds, and polar and charged substances dissolve in it while non-polar ones do not. Almost every property in this subtopic comes back to that one contrast between polar and non-polar. You also need the idea of a covalent bond from any chemistry course: two atoms sharing a pair of electrons.


1The idea in one paragraph

Life is built on carbon because a carbon atom makes four strong covalent bonds, so it can sit at the centre of chains, branches and rings of almost any size. Small units called monomers are joined into large polymers by condensation, which releases water, and split again by hydrolysis, which uses it. Carbohydrates are built from sugar monomers: glucose is soluble and easy to move, starch and glycogen pack glucose into compact stores, and cellulose turns the same glucose into strong fibres. Lipids are the molecules that do not dissolve in water. Triglycerides store twice as much energy per gram as carbohydrate and insulate the body; phospholipids have one water-loving end and one water-hating end, so they build membranes on their own; steroids are non-polar enough to slip straight through those membranes. Every one of those functions is explained by a detail of shape.

2Why life is built on carbon

A covalent bond is a pair of electrons shared between two atoms. It is strong, so a molecule held together by covalent bonds does not fall apart at the temperatures cells live at.

Carbon has four electrons available for bonding, so a carbon atom forms up to four covalent bonds. They can be four single bonds, or a mixture of single and double bonds (a double bond counts as two). Carbon bonds readily to other carbon atoms and to the other non-metals that living things use: hydrogen, oxygen, nitrogen, phosphorus and sulfur.

That combination is what makes carbon special. Because each carbon can bond to further carbons, you can build a backbone of any length, and because each one still has spare bonds, the backbone can branch, close into a ring, or carry side groups. Figure 1 shows the four basic skeleton shapes you should be able to name.

Figure 1 · One carbon atom, four bonds, endless skeletons Figure 1 · One carbon atom, four bonds, endless skeletons C four covalent bonds each one a shared pair of electrons C–C single bond C=C double bond C=O double bond Unbranched chain a fatty acid tail Branched chain the R-group of valine Single ring glucose, ribose Several fused rings steroids such as testosterone Carbon can bond to four other atoms, so it can build chains, branches and rings of any size.
Figure 1 · One carbon atom, four bonds, endless skeletons
  • Unbranched chains: the hydrocarbon tail of a fatty acid.
  • Branched chains: many amino acid side chains, and, at a larger scale, glycogen.
  • Single rings: glucose and ribose.
  • Several fused rings: the steroids, such as testosterone.

A note on units (nature of science). Biology moves between scales constantly, and the prefixes that do it are fixed by international agreement, so that "a micrometre" means exactly the same thing in every laboratory in the world. That agreement is what lets one scientist check another's measurements.

PrefixSymbolMultiply the unit byBiological example
kilok10³energy per gram of food, in kJ
centic10⁻²the length of a leaf, in cm
millim10⁻³the concentration of a solution, in mmol dm⁻³
microµ10⁻⁶the diameter of a cell, in µm
nanon10⁻⁹the thickness of a membrane, in nm

3Building and breaking polymers: condensation and hydrolysis

A monomer is a small molecule that can join to others like it; a polymer is a long chain of monomers. A macromolecule is simply a very large molecule, and the biological ones are mostly polymers.

Condensation joins two monomers with a covalent bond and releases a molecule of water. One monomer gives up an –OH group, the other gives up an –H, and those two become H₂O. Figure 2 shows the exchange.

Figure 2 · Condensation builds a polymer; hydrolysis takes it apart Figure 2 · Condensation builds a polymer; hydrolysis takes it apart monomer OH + H monomer condensation hydrolysis monomer O monomer + H₂O condensation: one water molecule is released for every bond made hydrolysis: one water molecule is split, its –H and –OH go back to the monomers Monomer Polymer Link monosaccharide polysaccharide glycosidic bond amino acid polypeptide peptide bond nucleotide nucleic acid phosphodiester bond The same two reactions build and break all three kinds of biological polymer.
Figure 2 · Condensation builds a polymer; hydrolysis takes it apart

The rule for counting follows directly: one water molecule for every bond made. Join 2 glucose molecules and one water is released. Join 100 glucose molecules into a chain and there are 99 bonds, so 99 water molecules are released.

Hydrolysis is the reverse. A water molecule is split: its –H goes to one monomer and its –OH to the other, and the bond between them breaks. The name says it: hydro for water, lysis for splitting. Digestion in your gut is hydrolysis, catalysed by enzymes, of polysaccharides to monosaccharides, proteins to amino acids, and nucleic acids to nucleotides.

The same pair of reactions builds all three kinds of biological polymer, which is why the guide asks you to know them together:

  • polysaccharides, from monosaccharides such as glucose (starch, glycogen, cellulose);
  • polypeptides, from amino acids (B1.2);
  • nucleic acids, from nucleotides (DNA and RNA, A1.2).

4Monosaccharides: pentoses, hexoses and glucose

A monosaccharide is a single sugar unit, the monomer of carbohydrates. Two sizes matter here. A pentose has five carbon atoms: ribose, in RNA, and deoxyribose, in DNA. A hexose has six: glucose, and also fructose and galactose.

In water most of these sugars close into a ring, and in the exam you will see them drawn that way. Figure 3 shows ribose and the two forms of glucose.

Figure 3 · A pentose and two hexoses, drawn as rings Figure 3 · A pentose and two hexoses, drawn as rings O CH₂OH OH H H OH H OH 1 2 3 4 5 O CH₂OH H OH OH H H OH H OH 1 2 3 4 5 6 O CH₂OH H OH OH H H OH OH H 1 2 3 4 5 6 (a) Ribose · a pentose (b) α-glucose · a hexose (c) β-glucose · a hexose 5 carbons: 4 in the ring, 1 above it 6 carbons: 5 in the ring, 1 above it –OH on carbon 1 points down 6 carbons, same as α –OH on carbon 1 points up Count the carbons, not the corners: the ring holds one oxygen, and one carbon sits outside it.
Figure 3 · A pentose and two hexoses, drawn as rings

How to tell a pentose from a hexose on a diagram. Count the carbon atoms, not the corners of the ring. The ring always contains one oxygen atom, and one carbon sits outside the ring on a CH₂OH group. So:

  • a five-sided ring (four carbons and an oxygen) plus one carbon outside = 5 carbons = pentose;
  • a six-sided ring (five carbons and an oxygen) plus one carbon outside = 6 carbons = hexose.

Counting ring corners gives the right answer for these two only by luck, and fails the day a diagram leaves the ring oxygen unlabelled. Count carbons.

α-glucose and β-glucose differ in one place only: the –OH group on carbon 1. In α-glucose it points down, below the ring; in β-glucose it points up. That small difference decides whether a chain of glucose becomes starch or cellulose, sections 5 and 6.

Glucose, and why its properties suit its job. Glucose is the sugar that animals carry in their blood and that every cell can respire. The guide names four properties, and each one connects to a use.

PropertyWhy glucose has itWhat it allows
SolubleFive –OH groups make it polar, so it forms hydrogen bonds with waterIt dissolves in the cytoplasm and in blood plasma
TransportableIt is soluble and smallIt is carried in solution to every cell in the body
Chemically stableThe ring does not react readily unless an enzyme acts on itIt can be moved and held without breaking down on the way
High energy yield from oxidationIts C–H and C–C bonds release energy when oxidised to CO₂ and water in respirationRoughly 16–17 kJ of energy per gram

The weakness of glucose is the other side of its solubility. Dissolved glucose raises the solute concentration of a cell, which draws water in by osmosis (B2.1). A cell that stored its fuel as free glucose would swell. The solution is to lock it up in a polymer.

5Starch and glycogen: storing glucose compactly

Plants store glucose as starch; animals and fungi store it as glycogen, mainly in the liver and muscles. Both are polymers of α-glucose, and Figure 4 shows their three forms.

Figure 4 · Three ways to store α-glucose compactly Figure 4 · Three ways to store α-glucose compactly (a) Amylose (starch) unbranched chain, 1,4 links only, coils into a helix (b) Amylopectin (starch) 1,4 chains with a 1,6 branch every so often (c) Glycogen (animals) far more branches: a dense, bushy granule α-glucose joined by a 1,4 link α-glucose carrying a 1,6 branch Coiling and branching pack glucose tightly. Every free end is a place to add or remove glucose.
Figure 4 · Three ways to store α-glucose compactly

Starch is a mixture of two molecules. Amylose is an unbranched chain of α-glucose joined by 1,4 links (carbon 1 of one glucose to carbon 4 of the next), and the angle of that link makes the chain coil into a helix. Amylopectin is also 1,4-linked, but every so often a 1,6 link starts a branch. Glycogen is built like amylopectin with far more branches, so it forms dense, bush-like granules.

The guide wants three properties, each explained by structure.

Compact. Coiling and branching fold a very long chain into a small space. A lot of glucose fits into a starch grain in a potato cell or a glycogen granule in a liver cell.

Relatively insoluble, so osmotically inactive. A single glucose dissolves; a molecule of thousands of glucose units does not, because it is too large to be surrounded and carried by water molecules. This is the reason, and it is not that starch is non-polar (it is covered in –OH groups). Because the store is insoluble, it does not raise the solute concentration inside the cell, and the cell does not take in water by osmosis.

Easy to build up and break down. Glucose is added to the ends of chains by condensation and removed from the ends by hydrolysis. A branched molecule has many ends, so many enzymes can work at once. That is why glycogen, the most branched, is also the fastest to mobilise: an animal that suddenly has to run needs glucose in seconds, and a plant never does.

6Cellulose: the same monomer as a building material

Cellulose is the main component of plant cell walls, and it is a polymer of β-glucose joined by 1,4 links. Because the –OH on carbon 1 points up in β-glucose, the only way to link carbon 1 of one unit to carbon 4 of the next is to turn every other glucose upside down. Figure 5 shows the result.

Figure 5 · Cellulose: straight chains of β-glucose, bundled by hydrogen bonds Figure 5 · Cellulose: straight chains of β-glucose, bundled by hydrogen bonds O O O O O O O O O O O O O O O O O O O O O chain 1 chain 2 chain 3 CH₂OH side: up, down, up… each unit flipped hydrogen bonds Flipping every other monomer keeps the chain straight, so chains lie side by side as microfibrils.
Figure 5 · Cellulose: straight chains of β-glucose, bundled by hydrogen bonds

Follow the chain of consequences, because this is exactly what a four-mark "explain" answer contains.

  1. Monomers alternate in orientation, each turned 180° relative to its neighbour.
  2. So the chain does not coil. It stays straight.
  3. Straight chains can lie side by side in parallel, close together.
  4. The many –OH groups of neighbouring chains form hydrogen bonds between the chains, cross-linking them.
  5. Bundles of cross-linked chains form microfibrils, which have very high tensile strength: they resist being pulled apart.
  6. So the cell wall can resist the pressure of water pushing outwards, and the plant cell becomes turgid instead of bursting.

One hydrogen bond is weak. Millions of them along parallel chains are not, which is the whole trick of cellulose.

Put sections 5 and 6 side by side and you have a textbook case of form and function. Starch and cellulose are both made of glucose, both joined by condensation, and both insoluble. One small change in the monomer, α against β, decides whether the polymer coils into a store or straightens into a fibre.

7Glycoproteins and cell–cell recognition

A glycoprotein is a protein with a carbohydrate chain attached. In the plasma membrane the carbohydrate sits on the outside of the cell, where other cells can meet it. The chains differ between cell types, between individuals and between species, so they work as identity tags: cells use them to recognise one another, and the immune system uses them to tell self from non-self.

The guide's example is the ABO blood group system, shown in Figure 6.

Figure 6 · ABO antigens: one sugar at the tip decides the blood group Figure 6 · ABO antigens: one sugar at the tip decides the blood group plasma membrane of a red blood cell (outside of the cell above) Group O no extra sugar Group A Group B Group AB shared core sugars extra sugar added by the A enzyme different sugar, B enzyme The protein and core chain are the same in everyone. The immune system reads the tip.
Figure 6 · ABO antigens: one sugar at the tip decides the blood group

Every person's red blood cells carry the same core carbohydrate chain on their surface glycoproteins. What differs is the final sugar.

  • Group O: the core chain only.
  • Group A: an enzyme adds one extra sugar to the tip of the chain, making the A antigen.
  • Group B: a slightly different enzyme adds a different sugar, making the B antigen.
  • Group AB: both enzymes are present, so both antigens are made.

An antigen is a molecule the immune system can recognise. A person with group A blood makes antibodies against the B antigen, because B is not part of "self" for them. If they are given group B blood, their antibodies bind to the B antigens on the donated cells and the cells clump together, which can be fatal. That is why blood is matched before a transfusion, and it shows the point of the whole section: one sugar, at the tip of one chain, is enough for the body to recognise a cell as its own or as foreign.

8Lipids: defined by what they will not dissolve in

Lipids are substances in living organisms that dissolve in non-polar solvents such as hexane but are only sparingly soluble in water. They are defined by that behaviour, not by one shared structure, so the group is varied: fats, oils, waxes (the waxy cuticle on a leaf) and steroids are all lipids.

The reason for the behaviour is in their structure. Lipids are built mostly of carbon and hydrogen in long chains or rings, and C–H bonds are almost non-polar. Water molecules are more attracted to each other than to a non-polar surface, so they hydrogen-bond among themselves and push the lipid away. That property, being hydrophobic ("water-fearing"), is the source of everything lipids do: they separate from water, they store energy without drawing water into cells, and they form the barrier of every membrane.

9Triglycerides and phospholipids, built by condensation

Both are built on glycerol, a small molecule with three carbon atoms, each carrying an –OH group. A fatty acid is a long hydrocarbon chain with a carboxyl group (–COOH) at one end. Figure 7 shows the two lipids made from them.

Figure 7 · Two lipids built on glycerol by condensation Figure 7 · Two lipids built on glycerol by condensation (a) Triglyceride glycerol O C O O C O O C O glycerol + 3 fatty acids → triglyceride + 3 H₂O 3 ester bonds formed (b) Phospholipid glycerol P phosphate group (often with a further polar group on it) O C O O C O glycerol + 2 fatty acids + phosphate → phospholipid + 3 H₂O 2 ester bonds, 1 phosphate link Each link is a condensation: an –OH on glycerol meets an –OH on the acid, and water leaves.
Figure 7 · Two lipids built on glycerol by condensation

A triglyceride forms when one glycerol links to three fatty acids. Each link is a condensation reaction between an –OH on glycerol and the –COOH of a fatty acid, forming an ester bond and releasing one water molecule. So:

glycerol + 3 fatty acids → triglyceride + 3 water

A phospholipid forms when one glycerol links to two fatty acids and one phosphate group. The two fatty acids join by ester bonds; the phosphate takes the third –OH position. It is still three condensation reactions, so three water molecules are released. The phosphate often carries a further polar group, but you are not asked to name one.

The difference in that third position is the difference in function. A triglyceride has three non-polar tails and nothing polar worth mentioning, so it is entirely hydrophobic and gathers in droplets. A phospholipid has a polar, charged head, which changes everything (section 12).

10Saturated, monounsaturated and polyunsaturated fatty acids

The chain of a fatty acid can hold different numbers of C=C double bonds, and Figure 8 shows what they do to its shape.

Figure 8 · Double bonds put kinks in fatty acid chains Figure 8 · Double bonds put kinks in fatty acid chains (a) Saturated no C=C COOH (b) Monounsaturated one C=C COOH (c) Polyunsaturated two or more C=C COOH straight chains pack tightly kinks keep chains apart more kinks, looser still higher melting point lower melting point Chains that sit close hold each other more strongly, so more heat is needed to melt them.
Figure 8 · Double bonds put kinks in fatty acid chains
  • Saturated: no C=C double bonds. Every carbon in the chain holds as many hydrogen atoms as it can, so the chain is "saturated" with hydrogen, and it is straight.
  • Monounsaturated: one C=C double bond.
  • Polyunsaturated: two or more C=C double bonds.

In natural fatty acids the double bonds are almost always of the kind that bends the chain, so each one puts a kink in it.

Why that changes the melting point. Straight saturated chains can pack tightly against each other, and chains in close contact attract one another more strongly. More heat is needed to separate them, so the melting point is high. Kinked chains cannot pack closely, the attractions between them are weaker, and the melting point is lower. Each extra double bond adds a kink and lowers the melting point further. The rule: more double bonds, lower melting point.

Where you find each kind. Lipids rich in saturated fatty acids are usually solid at room temperature: we call them fats. Lipids rich in unsaturated fatty acids are usually liquid: we call them oils.

  • Plants store energy mainly as oils, rich in unsaturated fatty acids, in seeds such as sunflower and olive. A plant does not keep itself warm, so its stores must stay liquid and usable at whatever temperature the seed or tissue happens to be at, often cool.
  • Endotherms, the birds and mammals that keep their bodies at a steady high temperature, store more saturated fat. Inside a warm body this fat is soft enough to be used; out of the body at room temperature it is solid, which is why butter and lard stand up on a kitchen table while olive oil pours.

11Triglycerides in adipose tissue: energy storage and insulation

Adipose tissue is tissue whose cells are filled with droplets of triglyceride. Mammals keep much of it under the skin and around organs.

Why triglycerides suit long-term energy storage. Oxidising a gram of lipid releases about 37 kJ, against about 17 kJ for a gram of carbohydrate, because lipids are richer in C–H bonds and poorer in oxygen. They are stored without water: triglyceride droplets exclude it, whereas glycogen is stored bound to water that adds mass but no energy. They are insoluble, so they have no osmotic effect, and chemically stable, so they keep for months. In numbers, an adult carrying 10 kg of stored triglyceride holds:

10 kg = 10 000 g
10 000 g × 37 kJ g-1 = 370 000 kJ
same energy as carbohydrate: 370 000 kJ ÷ 17 kJ g-1 = 21 765 g ≈ 21.8 kgmore than twice the mass, before adding the water glycogen holds

For an animal that carries its fuel, above all one that flies or migrates, that difference in mass decides the long-term store. Glycogen is kept anyway because it is quicker to mobilise, and its glucose can be respired with or without oxygen, whereas fat is broken down more slowly and only aerobically. So animals use both, as the table sets out.

Carbohydrate (glycogen, starch)Lipid (triglyceride)
Energy per gramabout 17 kJabout 37 kJ, roughly twice
Stored with water?yes, glycogen is hydratedno, stored as dry droplets
Osmotic effectnone, insolublenone, insoluble
Speed of releasefast, many chain ends to hydrolyseslower
Respired without oxygen?yes, glucose can beno
Typical roleshort-term storelong-term store, also insulation

Thermal insulation. Fat conducts heat poorly, so a layer of adipose tissue under the skin slows the loss of heat from a warm body to cold surroundings. How much insulation an animal needs depends on two things the guide asks you to relate.

  • Body temperature: an endotherm holds its body at a steady high temperature, so there is a gap between inside and outside, and heat flows across it continuously. The bigger the gap, the more insulation pays.
  • Habitat: water conducts heat away more than twenty times faster than air, so marine mammals in polar seas, such as seals and whales, carry a thick layer of blubber. Animals of hot, dry places tend to do the opposite: a camel stores fat concentrated in its hump rather than spread under the skin, so the rest of its body can lose heat freely.

12Phospholipids form bilayers because they are amphipathic

A phospholipid has two regions with opposite properties. The phosphate head is polar and charged, so it is hydrophilic ("water-loving"). The two fatty acid tails are non-polar, so they are hydrophobic. A molecule with a hydrophilic part and a hydrophobic part is amphipathic. Use that word; the guide requires it.

Figure 9 · A phospholipid is amphipathic, so in water it forms a bilayer Figure 9 · A phospholipid is amphipathic, so in water it forms a bilayer (a) One phospholipid phosphate head polar, hydrophilic hydrocarbon tails non-polar, hydrophobic (b) The bilayer that forms in water water water heads face the water tails hide in the middle No energy is spent: the bilayer is simply the arrangement in which no tail touches water.
Figure 9 · A phospholipid is amphipathic, so in water it forms a bilayer

In water, the heads are attracted to water molecules and the tails are pushed away from them. The arrangement that satisfies both at once is a bilayer, shown in Figure 9: two sheets of phospholipids, tails pointing inwards to form a hydrophobic core, heads pointing out into the water on both sides. No energy is spent building it and no enzyme is needed. The bilayer forms spontaneously, because it is the arrangement in which no tail is in contact with water. That self-assembly is the basis of every cell membrane, and B2.1 builds the whole membrane on it.

13Steroids pass through the bilayer

Steroids are lipids built on a skeleton of four fused rings: three six-sided rings and one five-sided ring. Different steroids carry different small groups on that skeleton, but the skeleton is how you recognise one. The guide names two, both hormones, drawn in Figure 10.

Figure 10 · Two steroids: four fused rings, few polar groups Figure 10 · Two steroids: four fused rings, few polar groups (a) Oestradiol OH CH₃ HO A B C D (b) Testosterone OH CH₃ CH₃ O A B C D Spot a steroid by its skeleton: three six-sided rings and one five-sided ring, fused. The polar –OH or =O groups are tiny beside the non-polar rings, so both molecules are hydrophobic.
Figure 10 · Two steroids: four fused rings, few polar groups
  • Oestradiol, the main oestrogen, a female sex hormone. Its first ring has alternating double bonds (drawn as a ring with a circle), and it carries an –OH at each end.
  • Testosterone, the main male sex hormone. It has an =O group at one end, an –OH at the other, and two methyl (–CH₃) groups.

Both molecules are almost entirely carbon and hydrogen, with one or two small polar groups. So they are non-polar, and a non-polar molecule can dissolve in the hydrophobic core of the phospholipid bilayer and pass straight through it by simple diffusion. That is why steroid hormones need no transport protein to enter a cell: they diffuse in and bind to receptors in the cytoplasm or nucleus. Glucose, by contrast, is polar and cannot cross the hydrophobic core, which is why it needs protein channels (B2.1).

How to identify a steroid in a Paper 1A diagram. Look for the four fused rings, three of six and one of five. If a molecule has one ring, it is not a steroid; if it has two separate rings joined by a bridge, it is not a steroid. The small groups tell you which steroid; the rings tell you it is one.

14Where marks are lost

Saying hydrolysis releases water. Condensation releases water; hydrolysis uses it. The name helps: hydrolysis splits (lysis) water (hydro).

Counting the ring corners instead of the carbons. A pentose or hexose is named for its carbon atoms. The ring holds an oxygen and one carbon sits outside it, so count carbons every time.

Saying starch is insoluble because it is non-polar. Starch is covered in polar –OH groups. It is insoluble because its molecules are too large. That is the answer the mark scheme wants.

Writing "cellulose is made of α-glucose". Starch and glycogen are α-glucose; cellulose is β-glucose. Get this one wrong and the whole explanation of straight chains collapses.

"Lipids contain more energy" without "per gram". A whale's glycogen store may hold more energy than a mouse's fat. The comparison is per gram, and it is about twice.

Defining saturated as "has no double bonds". Say "no double bonds between carbon atoms in the chain": a fatty acid always has a C=O in its carboxyl group.

Calling a phospholipid hydrophobic. Only its tails are. The whole molecule is amphipathic, and that is why it forms a bilayer instead of a droplet.

Saying steroids cross membranes "because they are small". Glucose is small too and cannot. Steroids cross because they are non-polar, so they dissolve in the hydrophobic core.

15Draw it right

Two drawings are asked for directly in this subtopic, and two more are used in answers.

  1. α-glucose: a six-sided ring with O at the top right; carbon 6 in a CH₂OH group above carbon 5; the –OH on carbon 1 pointing down. Number the carbons if you have time; it earns the benefit of the doubt.
  2. β-glucose: identical, except the –OH on carbon 1 points up. Draw the two side by side if asked to distinguish them, and circle the difference.
  3. Ribose: a five-sided ring with O at the top, CH₂OH above carbon 4, and –OH on carbons 1, 2 and 3.
  4. Condensation: show the –OH from one monomer and the –H from the other, and write H₂O as a product. A condensation drawn without the water scores nothing.
  5. Triglyceride: glycerol with three fatty acid chains attached by ester bonds; write "+ 3 H₂O".
  6. Phospholipid: a circle labelled phosphate head, hydrophilic and two lines labelled fatty acid tails, hydrophobic. For a bilayer, tails meet in the middle and heads face water on both sides.
  7. Steroid: four fused rings, three six-sided and one five-sided, in that arrangement.
  8. Label every drawing, and refer to it in your writing.

16Try it

Marks in brackets. Answers and marker's notes are at the end.

Q1. Which reaction releases water? 1 mark

A. Digestion of starch to maltose

B. Formation of a dipeptide from two amino acids

C. Breakdown of a triglyceride to glycerol and fatty acids

D. Hydrolysis of glycogen to glucose

Q2. The table gives approximate melting points of four fatty acids. Each has a chain of 18 carbon atoms. 5 marks

Fatty acid (18 carbons)Number of C=C double bondsApproximate melting point / °C
stearic acid069
oleic acid113
linoleic acid2−5
linolenic acid3−11

(a) Describe the relationship between the number of double bonds and the melting point. 1 mark

(b) Calculate the difference in melting point between stearic acid and oleic acid. 1 mark

(c) Explain the relationship you described in (a). 2 marks

(d) Suggest, with a reason, which of these fatty acids would be least common in an oil stored in the seeds of a plant from a cold climate. 1 mark

Q3. Explain how the structure of cellulose is related to its function in plant cell walls. 4 marks

Q4. Compare and contrast carbohydrates and lipids as energy storage compounds in animals. 5 marks

Q5. A migrating bird lays down 12 g of triglyceride before its flight. Using 37 kJ g⁻¹ for lipid and 17 kJ g⁻¹ for carbohydrate, calculate the energy stored, and the mass of glycogen that would store the same energy. Give your answer to three significant figures. 2 marks

Q6. Testosterone enters its target cells without passing through any membrane protein, whereas glucose cannot. Explain this difference. 3 marks

17In one breath

Carbon makes four covalent bonds, so it builds chains, branches and rings. Condensation joins monomers and releases one water per bond; hydrolysis splits water to break the bond. Pentoses have five carbons, hexoses six: count carbons, not corners. Glucose is soluble, transportable, stable and energy-rich. Starch and glycogen are coiled, branched polymers of α-glucose: compact, insoluble because they are large, and quick to use because they have many ends. Cellulose is β-glucose with every other unit flipped, so its chains are straight, parallel and hydrogen-bonded into strong microfibrils. Glycoproteins label the cell surface, and one tip sugar makes the A or B antigen. Lipids dissolve in non-polar solvents, not water. Glycerol plus three fatty acids makes a triglyceride; swap one fatty acid for a phosphate and you have a phospholipid; either way three water molecules leave. More C=C double bonds mean more kinks and a lower melting point, so plants store oils and endotherms fats. Triglycerides store about twice the energy per gram of carbohydrate, without water, and insulate. Phospholipids are amphipathic, so they form bilayers by themselves. Steroids have four fused rings, are non-polar, and diffuse straight through the bilayer.


Answers

Q1. B. Forming a dipeptide is a condensation reaction and releases one water molecule. A, C and D are all hydrolysis reactions, which use water. B only.

Q2. (a) As the number of double bonds increases, the melting point decreases. (b) 69 − 13 = 56 °C. (c) Each C=C double bond puts a kink in the hydrocarbon chain; kinked chains cannot pack as closely together, so the attractions between neighbouring chains are weaker and less heat is needed to separate them. (d) Stearic acid, because with no double bonds it has the highest melting point and would be solid at low temperatures, so the stored oil would not stay liquid. (a) 1 for the negative relationship stated as a trend. (b) 1 for 56 °C with the unit. (c) 1 for double bonds causing kinks or bends, 1 for looser packing leading to weaker attraction between chains and a lower melting point. (d) 1 for stearic acid with the reason. "Unsaturated fats are healthier" scores 0 anywhere in this question: it is not what was asked.

Q3. Cellulose is a polymer of β-glucose. In a β-1,4 link each glucose is turned 180° relative to its neighbour, so the chain is straight and unbranched rather than coiled. Straight chains lie parallel and close to one another, and hydrogen bonds form between –OH groups on neighbouring chains, cross-linking them. Bundles of these chains form microfibrils with very high tensile strength, so the cell wall resists the outward pressure of water and the cell does not burst. 1 for β-glucose, 1 for alternating orientation giving straight chains, 1 for hydrogen bonds between parallel chains or microfibrils, 1 for tensile strength linked to a function of the wall. An answer that describes structure with no function scores at most 3.

Q4. Similarities: both are used by animals to store energy; both stores (glycogen and triglyceride) are insoluble in water so have no osmotic effect; both are formed by condensation and mobilised by hydrolysis. Differences: lipids release about twice as much energy per gram as carbohydrates (about 37 kJ against 17 kJ); triglycerides are stored without water whereas glycogen is stored hydrated, so fat is a lighter store; glycogen is mobilised faster, because it is highly branched with many ends, and its glucose can be respired anaerobically, so glycogen is a short-term store and triglyceride a long-term store; triglycerides in adipose tissue also provide thermal insulation, which glycogen does not. 1 per valid point, at least one similarity and at least one difference needed for full marks. Differences must be stated as comparisons ("lipids…, whereas carbohydrates…"). "Lipids have more energy" without "per gram" scores 0.

Q5.

energy = 12 g × 37 kJ g-1 = 444 kJ
mass of glycogen = 444 kJ ÷ 17 kJ g-1 = 26.1 g

A1 for 444 kJ, A1 for 26.1 g. Accept 26 g. An answer of 26.12 or more figures loses the second mark if the question's "three significant figures" is ignored.

Q6. Testosterone is a steroid, and steroids are non-polar (hydrophobic). The core of the phospholipid bilayer is made of non-polar hydrocarbon tails, so testosterone can dissolve in it and diffuse straight across. Glucose is polar, with many –OH groups, so it cannot pass through the hydrophobic core and must cross through a protein channel or carrier. 1 for testosterone non-polar or hydrophobic, 1 for the hydrophobic core of the bilayer allowing it through, 1 for glucose polar and blocked by the core. "Testosterone is small" scores 0: size is not the reason.


Educerie · written from the published IB Diploma Programme Biology guide, first assessment 2025, section B1.1 Carbohydrates and lipids. Original text, examples and questions. Diagrams drawn by Educerie. Last reviewed 25 September 2026.

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